TEST tomorrow in physics and on this problem

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SUMMARY

The discussion focuses on a physics problem involving a light-rail train that accelerates from rest at 1.4 m/s² for 15 seconds, travels 1100 meters at constant speed, and then decelerates at 2.2 m/s² until it stops. The total distance between the stations is determined to be 1400 meters, and the total time taken is 77 seconds. Key equations used include Vf = Vo + at and x = 1/2(Vf + Vo)t, which are essential for solving motion problems involving acceleration and deceleration.

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Homework Statement



A light-rail train going from one station to the next on a straight section of track accelerates from rest at 1.4 { m/s^2} for 15 { s}. It then proceeds at constant speed for 1100 { m} before slowing down at 2.2 { m/s^2} until it stops at the station.

What is the distance between the stations?

How much time does it take the train to go between the stations?

Homework Equations


(vx)f= (vx)i + ax\Deltat
xf= xi + (vx)i\Deltat + 1/2ax(\Deltat)2

(vx)f2= (vx)i2+2ax\Deltax

The Attempt at a Solution



I already know the answer but I can't figure out how to get to the right answer...
d= 1400m
t=77s
 
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Split the question into three different parts. Use equations Vf = Vo + at, x= 1/2(Vf + Vo)t.

For the first part, you are given Vo, a, t. You need to first find Vf, then x.

For the second part, you are given x and constant v. You must find t. Think about the units.

For the third part, you are given a (remember, it's deccelerating so it's - ), Vo, and Vf. Find t, then x.

At the end, add up all the times from the 3 parts to get 77s. And add the displacements together to get 1400m (I got 1357.5m, but 1400m is correct for the number of sig figs).

I hoped that helped, and that it wasn't too much information on how to solve the question.
 
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