Testing Series Convergence/Divergence: ∑ (-1)^(n)/ (1+1/n)^(n^2)

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SUMMARY

The series ∑ (-1)^(n)/ (1+1/n)^(n^2) is analyzed for convergence using the root test. The limit as n approaches infinity simplifies to 1/(1+1/n+1)^(n+1^2) * [(1+1/n)^(n^2)]/1. The discussion reveals that applying the ratio test complicates the process, while the root test provides a clearer path to determine convergence or divergence. Ultimately, the series converges conditionally.

PREREQUISITES
  • Understanding of series convergence tests, specifically the root test and ratio test.
  • Familiarity with limits and asymptotic analysis in calculus.
  • Knowledge of exponential functions and their properties.
  • Basic algebraic manipulation skills for simplifying expressions.
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  • Study the application of the root test in depth, focusing on its conditions and limitations.
  • Explore the ratio test and its effectiveness compared to other convergence tests.
  • Investigate asymptotic behavior of functions, particularly in the context of series.
  • Practice solving various series convergence problems to reinforce understanding.
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Test the following Series for Convergence (absolute or conditional) or divergence

∑ (-1)^(n)/ (1+1/n)^(n^2)

I know we solve it with the root test but i reached at a point where i don't know how to cancel it out

----

lim(n--> infinity)= 1/(1+1/n+1)^(n+1^2) *[ (1+1/n)^(n^2)]/1

What do i do after this?
 
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[tex] \ldots=\frac{(1+\frac{1}{n})^{n^2}}{(1+\frac{1}{n+1})^{n^2+2n+1}}=<br /> (1+\frac{1}{n+1})^{-2n-1}\left[\frac{(n+1)^2}{n(n+1)}\right]^{n^2}<br /> \sim e^{-2}\left(\left[1+\frac{1}{n(n+1)}\right]^{n^2+n}\left)^\frac{n^2}{n^2+n}<br /> \sim e^{-1}[/tex]
 
Simkate said:
Test the following Series for Convergence (absolute or conditional) or divergence

∑ (-1)^(n)/ (1+1/n)^(n^2)

I know we solve it with the root test but i reached at a point where i don't know how to cancel it out

----

lim(n--> infinity)= 1/(1+1/n+1)^(n+1^2) *[ (1+1/n)^(n^2)]/1

What do i do after this?

You are using the ratio test, not the root test. The problem is a lot easier if you actually use the root test.
 

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