Textbook 'The Physics of Waves': Lifetime of SHM Oscillators

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The discussion centers on the concept of "lifetime" in oscillators, particularly focusing on underdamped, overdamped, and critically damped systems. It clarifies that while the lifetime of underdamped oscillators is defined as the time for amplitude to reduce by half, similar definitions can apply to overdamped and critically damped oscillators, although they typically do not exhibit oscillations. The term "lifetime" can be vague, with various definitions such as the time for amplitude reduction by factors of 1/e or 1/sqrt(e). The equations for overdamped and critically damped oscillators differ from underdamped ones, but the underlying principle of amplitude decay remains consistent across all types. Understanding these distinctions is crucial for accurately describing the behavior of different oscillator types.
brettng
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Homework Statement
The lifetime of the state in free oscillation is of order ##\frac 1 { \Gamma }##.
Relevant Equations
$$\tau=\frac { \ln(4) } { \Gamma }$$
Reference textbook “The Physics of Waves” in MIT website:
https://ocw.mit.edu/courses/8-03sc-...es-fall-2016/resources/mit8_03scf16_textbook/

Chapter 2 - Section 2.3.2 [Page 47] (see attached file)


Question: In the content, it states that the lifetime of the state in free oscillation is of order ##\frac 1 { \Gamma }##. To my understanding, it means particularly the half-life of underdamped oscillators with position ##x\left( t \right)##:
$$x\left( t \right)=Ae^{ -\frac {\Gamma t} {2} }\cos(\omega t-\theta)$$

However, could I consider the "half-life" of overdamped oscillators and critically damped oscillators?

If so, would it still be of order ##\frac 1 { \Gamma }##?

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brettng said:
In the content, it states that the lifetime of the state in free oscillation is of order ##\frac 1 { \Gamma }##.
Do you understand what is meant here by "lifetime"? Also, what do the equations for ##x(t)## look like over damped and critically damped oscillators?
 
DrClaude said:
Do you understand what is meant here by "lifetime"? Also, what do the equations for ##x(t)## look like over damped and critically damped oscillators?
I understand that lifetime means that the oscillation amplitude reduces by a factor of 2.

So, why can’t we still consider the “lifetime” of overdamped and critically damped oscillators by using the same definition?
 
In practice, people only refer to "oscillations" wrt underdamped systems. Otherwise we tend to use "rise time"; usually defined as 10-90%, tr = 2.2τ. But it is the equation that holds the real answers, the rest is just jargon.
 
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brettng said:
I understand that lifetime means that the oscillation amplitude reduces by a factor of 2.
That would be the half-life. Lifetime itself is actually more vague. For instance, in this case one could take ##\tau = 1/\Gamma##, which would be the time for the oscillation amplitude to be reduced by a factor ##1/\sqrt{e}##, or ##\tau = 2/\Gamma##, for a reduction of the amplitude by ##1/e##. They are all of order ##1/\Gamma##, as the text states, and as @DaveE stated, they all relate to a decrease of the amplitude of oscillations, and different terminology is used for critically and over-damped oscillators, which do not actually oscillate.
 
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Thank you so much for your help!!!!!!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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