- #1

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I know it has a simple solution. but I really have mixed up!!!

Thanks.

- Thread starter somy
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- #1

- 137

- 0

I know it has a simple solution. but I really have mixed up!!!

Thanks.

- #2

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- #3

HallsofIvy

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If the two lines actually intersect, then the angle is given by

[tex]cos(\theta)= \frac{u\cdot v}{|u||v|} [/tex] where u and v are any vectors pointing in the direction of each line. You can use the point of intersection and one point on each line to define those vectors.

If the line do**not** intersect (the "typical" case in 3d) then there is no angle between them.

[tex]cos(\theta)= \frac{u\cdot v}{|u||v|} [/tex] where u and v are any vectors pointing in the direction of each line. You can use the point of intersection and one point on each line to define those vectors.

If the line do

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- #4

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Thank you. I'll try it!!!

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