The Atomic Mass - Calculating the Weight of Gallium Atoms

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SUMMARY

The average atomic mass of a gallium atom is 69.72 amu, derived from its two isotopes. To determine how many gallium atoms weigh 69.70 amu in a sample of 1.7 quintillion atoms, one must apply the formula: 69.72 = [(number of Isotope 1)(atomic mass) + (number of Isotope 2)(atomic mass)] / total number of atoms. This calculation allows for the determination of the ratio of isotopes present in the sample, which can then be used to find the specific number of atoms corresponding to each isotope.

PREREQUISITES
  • Understanding of atomic mass and isotopes
  • Familiarity with the concept of average atomic mass
  • Basic algebra for solving equations
  • Knowledge of the Periodic Table of Elements
NEXT STEPS
  • Research the isotopes of gallium and their respective atomic masses
  • Learn how to calculate average atomic mass using weighted averages
  • Study the concept of mole and Avogadro's number for large quantities of atoms
  • Explore the application of isotopic abundance in chemistry
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Chemistry students, educators, and anyone interested in understanding atomic structure and isotopic calculations.

rumaithya
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The Atomic Mass!

Hello, I have a problem of getting the answer of this question and I still don't understand it. The question is

According to the Periodic Table, the average atomic mass of a gallium atom is 69.72 amu. Naturally occurring gallium has two nuclides ("isotopes"). If you have a pile with 1,700,000,000,000,000,000 atoms of gallium, how many of them will weigh 69.70 amu?

What I though is that the answer is "1,700,000,000,000,000,000" and I thought it's same as when we say we have a red apple and how many red apples are in 1700000000 red apples. That's sounds strange and probbly wrong I'm not sure . Do we have to do this -> 1,700,000,000,000,000,000 / 69.72 to get the answer?

... Any ideas?
Thanks
 
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Find the atomic mass of the two gallium isotopes.

69.72 =[(number of Isotope 1)(atomic mass)+(number of Isotope 2)(atomic mass)] / 1,700,000,000,000,000,000

Solve so that you obtain (number of isotope 1)/(number of isotope 2)

Try to do it yourself first.

The above will be the proportion. For example if the proportion is 1/3 the total percentage of a particular isotope will be either 1/4 or 3/4. Multiply this percentage with 1,700,000,000,000,000,000.
 
Last edited:
Thanks a lot for your help :smile:
 

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