The attractive gravitational forces between two people separated by 1.5 meters

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SUMMARY

The discussion focuses on calculating the gravitational and centrifugal forces between two individuals separated by 1.5 meters, with weights of 80 kg and 70 kg. The gravitational force is calculated using the formula F = Gm1m2/r², yielding a force of 1.667 x 10^-7 N. Participants explore the implications of angular velocity and the concept of the center of mass, concluding that the center of mass remains stationary unless acted upon by an external force. The conversation emphasizes the need to consider the system's dynamics when analyzing forces and motion.

PREREQUISITES
  • Understanding of Newton's Law of Gravitation (F = Gm1m2/r²)
  • Knowledge of centrifugal force calculations (F = mv²/r)
  • Familiarity with angular velocity concepts (ω = v/r)
  • Basic principles of center of mass and momentum conservation
NEXT STEPS
  • Learn how to calculate angular velocity in rotating systems
  • Explore the implications of gravitational force in non-point mass systems
  • Study the dynamics of two-body systems and external forces
  • Investigate the effects of modeling complex shapes on gravitational attraction
USEFUL FOR

Physics students, educators, and anyone interested in understanding gravitational interactions and rotational dynamics in two-body systems.

robax25
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Homework Statement
calculate attractive forces between you and your friend if your body weight is 80 kg and your friend weight is 70kg. The distance is 1,5m.

At which angular velocity could you spain about a common center such that the centrifugal forces don't drive you away from each other?

what is the maximum force if the distance was zero?
Relevant Equations
F= Gm1M2/r²
v=ω * r
F= Gm1m2/r² = 1.667*10^-7 N.
I don't understand How to calculate angular velocity?
 
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Possibly start by finding the distance from each of you to the common center. Where will the center be?
 
0.75m. Do you think that centrifugal force is 1.667*10^-7 N?

Centrifugal force is F= mv²/r,
F= mω²r.
 
robax25 said:
0.75m. Do you think that centrifugal force is 1.667*10^-7 N?

Centrifugal force is F= mv²/r,
F= mω²r.
If the two of you were to spin about that center, would your center of mass be moving?

Does that suggest that some other center might be a more proper choice?
 
robax25 said:
Homework Statement:: calculate attractive forces between you and your friend if your body weight is 80 kg and your friend weight is 70kg. The distance is 1,5m.

At which angular velocity could you spain about a common center such that the centrifugal forces don't drive you away from each other?

what is the maximum force if the distance was zero?
Relevant Equations:: F= Gm1M2/r²
Isn't this formula only valid for point masses or spherically symmetric objects? That said, I assume it's what you are supposed to use.
 
jbriggs444 said:
If the two of you were to spin about that center, would your center of mass be moving?

Does that suggest that some other center might be a more proper choice?
yes. Center of mass will move.
 
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robax25 said:
yes. Center of mass will move.
That requires an external force acting on the two-body system, doesn't it?
 
PeroK said:
Isn't this formula only valid for point masses or spherically symmetric objects? That said, I assume it's what you are supposed to use.
I need to calculate centrifugal force and angular velocity.
PeroK said:
That requires an external force acting on the two-body system, doesn't it?
yes. It does.
 
robax25 said:
I need to calculate centrifugal force and angular velocity.

yes. It does.
What provides the external force to move the centre of mass?
 
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As far as, I understand that there is only gravitational force acts on them .I mean F= mg if they Spain, the force will be same. Obviously, the F=Gm1m2/r² will not be the force that I have thought the centrifugal force.
 
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robax25 said:
As far as, I understand that there is only gravitational force acts on them .I mean F= mg if they Spain, the force will be same. Obviously, the F=Gm1m2/r² will not be the force that I have thought the centrifugal force.
Right. Only gravity. Since that is an internal force rather than an external force, momentum must be conserved. The center of mass cannot move.

It follows that the two objects cannot both circle about their geometric center. What center can they circle about so that the center of mass does not move?
 
  • #12
PeroK said:
Isn't this formula only valid for point masses or spherically symmetric objects? That said, I assume it's what you are supposed to use.
Out of interest, I modeled the bodies as stacks of 11 perfect spheres of various radii, roughly forming the shape of people.
It cut the gravitational attraction by about 10% compared with a single sphere for each.
 
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  • #13
haruspex said:
Out of interest, I modeled the bodies as stacks of 11 perfect spheres of various radii, roughly forming the shape of people.
It cut the gravitational attraction by about 10% compared with a single sphere for each.
Treat the system as a spherical 70kg chicken and a spherical 80kg chicken (in a vacuum) ...
E.g.
 
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