The average emf created by the earths magnetic field.

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SUMMARY

The average electromotive force (emf) generated by a 15-turn cable with a diameter of 0.5 meters, when flipped 180 degrees in 2 seconds within the Earth's magnetic field of 0.5 microtesla, is calculated using the formula e = -n * r² * (ΔB/ΔT). The values used in the calculation are n = 15, ΔB = 1 microtesla, and ΔT = 2 seconds, resulting in an emf of approximately -0.468 microvolts. The alternative calculation using the area of the cable yields an emf of approximately 0.098 microvolts.

PREREQUISITES
  • Understanding of electromotive force (emf) concepts
  • Familiarity with magnetic fields and their measurements in tesla
  • Knowledge of basic calculus for understanding rate of change
  • Proficiency in applying formulas related to electromagnetic induction
NEXT STEPS
  • Study Faraday's Law of Electromagnetic Induction
  • Explore the implications of magnetic field strength on emf generation
  • Learn about the applications of emf in electrical engineering
  • Investigate the effects of varying the number of turns in a coil on induced emf
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Students in physics, electrical engineers, and anyone interested in the principles of electromagnetic induction and its practical applications.

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Homework Statement


What is the average emf created by a 15 turn cable that is .5 meters in diameter, lies flat with the surface of the Earth and is flipped 180 degrees in 2 seconds?
*Assume the Earth produces a magnetic field of .5 micro Tesla.


Homework Equations



e=-n*r^2*delta B/delta T

The Attempt at a Solution



n=15
delta B=.5*10^-6 minus -.5*10^-6 =1*10^-6 Tesla.
Delta T= 2 seconds
r=.25

e=-.468 micro Volts?
 
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e=-π*r^2*delta B/delta T
= π*(.25)²*(1x10^-6)/2 = .098 x 10^-6
 

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