The correct movement of charge in PN junction

[Kidphysics]

Homework Statement

I've been reading and I just want to make sure that this is the correct way which pv cells work, I feel this is not correct. I want to find where I am wrong.

Once the p and n doped semiconductors are put together some carriers migrate and combine to form a depletion zone and have buildup of opposite ion charges. Now when a photon with enough energy hits an electron that is across the depletion zone (black photon) the photon has sufficient energy to cross the zone, following the electric field over to where the majority electron carriers are (we hope that it doesn't recombine with the positive holes) and if it successfully reaches the other side it flows across the wire?

Also I added the brown photon, I assume this ehp just gets recombined.

Homework Equations

http://pveducation.org/pvcdrom/solar-cell-operation/light-generated-current

edit* the red circle was an electron, so I believe my diagram is correct!

The Attempt at a Solution

http://imageshack.us/photo/my-images/854/pnjunction.png
tried to draw a diagram. Wouldn't mind drawing a few more so that I can understand fully.

 

[member 553083]

Your diagram is correct.PV cells work by taking advantage of the potential difference created by the junction between p-type and n-type materials. When a photon with sufficient energy strikes the junction, it can excite an electron from the valence band to the conduction band. This electron is then driven by the electric field of the junction to the n-type side, where it can be collected as current. The holes left behind in the p-type side are driven to the opposite side of the junction. The brown photon is not used in the PV cell because it does not have enough energy to excite the electron to the conduction band. Instead, it just gets recombined with the holes in the p-type side.