The electric potential of 2 hollow concentric spherical shells

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SUMMARY

The discussion focuses on calculating the electric potential difference between two concentric conductive hollow spherical shells, where the inner shell has a radius R1 and charge +q, and the outer shell has a radius R2 and charge -q. The correct expression for the potential difference is derived using the superposition principle, resulting in V = q / (4 pi ε0) (1/r - 1/R2) for the region between the shells. This formula is validated by participants in the discussion, confirming its accuracy.

PREREQUISITES
  • Understanding of electric potential and charge distribution
  • Familiarity with the superposition principle in electrostatics
  • Knowledge of the formula for electric potential due to a point charge
  • Basic concepts of conductive materials and spherical geometry
NEXT STEPS
  • Study the derivation of electric potential for spherical conductors
  • Explore the implications of the superposition principle in electrostatics
  • Learn about Gauss's Law and its application to spherical charge distributions
  • Investigate the behavior of electric fields in conductive materials
USEFUL FOR

Students studying electrostatics, physics educators, and anyone interested in understanding electric potential in conductive systems.

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Homework Statement


Consider two concentric conductive hollow spherical shells. The inner shell has radius R1 and holds the charge +q. The outer shell has charge R2 and holds charge -q. Determine an expression for the potential difference between the shells.

Homework Equations



V = q / (4 pi ε0 r) when r greater or equal to the radius of the shell

V = q / (4 pi ε0 R) when r is less than the radius (R) of the shell

The Attempt at a Solution



I said due to fact that electric potential has superposition principle. The total electric potential between the shells:
therefore: V = q / (4 pi ε0) (1/r - 1/R2)
I am unsure if this is true or not any help would be appreciated, Thanks
 
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Yup, looks right to me.
 

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