Penultimate Messages 26 Reaction score 0 Thread starter Jun 18, 2009 #1 Whats the fifth derivate of the function [tex]y=x lnx[/tex] ? y(5)
qntty Messages 289 Reaction score 4 Jun 18, 2009 #2 Show some work first and indicate where you got stuck.
ideasrule Homework Helper Messages 2,286 Reaction score 0 Jun 18, 2009 #3 Not to sound too harsh, but if you can't even do a derivative as simple as xlnx, you won't do well on tomorrow's exam. Try reviewing: (1) product rule (2) quotient rule (3) chain rule Once you do so, the question you asked should be easy to solve.
Not to sound too harsh, but if you can't even do a derivative as simple as xlnx, you won't do well on tomorrow's exam. Try reviewing: (1) product rule (2) quotient rule (3) chain rule Once you do so, the question you asked should be easy to solve.
tiny-tim Science Advisor Homework Helper Messages 25,837 Reaction score 258 Jun 19, 2009 #4 Penultimate said: Whats the fifth derivate of the function [tex]y=x lnx[/tex] ? y(5) Hi Penultimate! It must mean the fifth derivative, ie the derivative of the fourth derivative, ie … d/dx( d/dx( d/dx( d/dx( d/dx(xlnx))))). How far have you got?
Penultimate said: Whats the fifth derivate of the function [tex]y=x lnx[/tex] ? y(5) Hi Penultimate! It must mean the fifth derivative, ie the derivative of the fourth derivative, ie … d/dx( d/dx( d/dx( d/dx( d/dx(xlnx))))). How far have you got?