The force required to raise a bridge/lever to an angle?

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SUMMARY

The discussion focuses on calculating the force required to raise a bascule bridge span to specific angles, particularly 38° and 85°. The spans of the Tower Bridge weigh 1 x 10^8 kg and the total weight is 9.8 x 10^8 N. The torque required to raise the span is calculated using the formula torque = r * F * sin(theta), where the center of gravity is located at 15.25 m. It is established that the torque needed to raise the span is variable, depending on the angle, and the maximum torque occurs when the arm is level.

PREREQUISITES
  • Understanding of torque and its calculation using the formula torque = r * F * sin(theta)
  • Knowledge of the concept of center of gravity and its significance in mechanics
  • Familiarity with the principles of bascule bridges and their operational mechanics
  • Basic trigonometry, specifically the use of sine and cosine functions in physics
NEXT STEPS
  • Study the mechanics of bascule bridges and their design principles
  • Learn about calculating torque in various mechanical systems
  • Explore the role of center of gravity in static and dynamic equilibrium
  • Investigate the effects of different angles on torque and force in lever systems
USEFUL FOR

Engineering students, mechanical engineers, and anyone interested in the mechanics of movable bridges and torque calculations.

helppls

Homework Statement


Tower bridge in London is an example of a bascule bridge (moveable bridge) where each part that is raised up is called a ‘span’. In this photo, the two spans are raised to an angle of 38° to let two tug boats through. Each span is 30.5 m long and weighs 1 x 108 kg (you can assume that the mass is distributed evenly).
a) Calculate the force required to raise one span to an angle of 38°
b) How does this force change if a span is raised to an angle of 85°?


I know that the center of gravity is at 15.25 m , which should then be the distance R
the bridge weighs 9.8*10^8 N

Homework Equations


torque = r*F
torque = r*F*sin(theta)

The Attempt at a Solution


a) the torque, I think, is
15.25 * (9.8 x 10^8) *sin(38) = 9.2 x 10^9 Nm ... but I don't know how to find the force required?
b) I am assuming that the force required lessens as you increase the angle of the bridge. I'm stuck.
 
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helppls said:
In this photo
What photo? You did not provide it.
 
tower-bridge1.jpg


sorry, yeah, it's just a photo of the bridge
 
helppls said:
Calculate the force required to raise one span to an angle of 38°
There are two troubling aspects to that wording.
First, as you appear to have realized, it does not require any particular force; what it does require is torque.
Secondly, does it really want the torque to raise it to that angle or the torque to hold it at that position? You have attempted to answer the second. However, check your trig choice.
 
Thanks for your response,
should I use cosine to make the force acting perpendicular to r?
If I'm just calculating the torque to hold it in position, how do I calculate the torque required to raise it to that position? Wouldn't that be variable?

I've been struggling with the wording on this assignment :(
 
helppls said:
should I use cosine to make the force acting perpendicular to r?
You need the perpendicular distance ("moment arm") from the pivot to the line of action of the load force.
helppls said:
how do I calculate the torque required to raise it to that position? Wouldn't that be variable?
Yes, but it has a maximum. To raise it you need to achieve that maximum torque.
 
haruspex said:
You need the perpendicular distance ("moment arm") from the pivot to the line of action of the load force.

Yes, but it has a maximum. To raise it you need to achieve that maximum torque.
Thank you! This makes sense. So I need to calculate the torque when the arm is level as this would have the maximum horizontal distance from the pivot arm and thus the maximum torque.
 
helppls said:
Thank you! This makes sense. So I need to calculate the torque when the arm is level as this would have the maximum horizontal distance from the pivot arm and thus the maximum torque.
Yes.
 

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