The gravitational force between and around 2 objects

Click For Summary
SUMMARY

The discussion focuses on simplifying the calculation of gravitational forces between two identical spaceships, emphasizing the importance of the center of mass in the analysis. The participants conclude that it is ineffective to treat the spaceships separately due to the gravitational force reaching zero at the midpoint. Instead, they recommend using the center of mass as a reference point for solving the problem, which aids in applying momentum conservation principles effectively.

PREREQUISITES
  • Understanding of gravitational force and its mathematical representation
  • Familiarity with the concept of center of mass in physics
  • Basic knowledge of integral calculus for force calculations
  • Experience with dynamics and rotational motion principles
NEXT STEPS
  • Study gravitational force equations in detail, particularly for multiple bodies
  • Learn about the center of mass and its applications in physics problems
  • Explore integral calculus techniques for calculating forces in continuous systems
  • Investigate momentum conservation laws in dynamic systems
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding gravitational interactions and dynamics involving multiple bodies in space.

robert80
Messages
66
Reaction score
0

Homework Statement


These days I am having the exam for physics 1. Could you please give me the idea, howto simplify the following exercise? You have 2 spaceships of the same shape and they are from the same material. You can have circular or eliptic spaceships for instance. Now you must draw the graph how the force is changing on the straight line between the centres of gravity.



Homework Equations





The Attempt at a Solution



Its surelly not possible to look at them seperatelly and simply sum the graphs as the force in the middle of them becomes 0. And there is no zero point in the centre of the masses too. Is it possible when you calculate the gravity from 1 spaceship and solve the integrals in 1 spaceship and around 1 spaceship is than possible to transform the graph and sum both graphs, that you get zero point then? How you do that? Or is there any other way to simplify this problem? Thanks
 
Physics news on Phys.org
by looking the centre of mass, you can seek a solution. for the bodies are same, the centre of mass (as position) remains constant. this state, can become a reference the solving problem (momentum conservation relative to the centre of mass...).
 
Ok thanks, what a brilliant solution. Havent thought of that. But its true that if you take the centre of the mass coordinate system in planty of cases is very good when doing the dynamics for instance... Or rotation. Havent thought of that in this exercise.
 

Similar threads

Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
12
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
15
Views
2K