What is the instantaneous velocity of a freely falling object 10 s after it is released from a position of rest? What is its average velocity during this 10 s interval? How far will it fall during this time?(adsbygoogle = window.adsbygoogle || []).push({});

I had asked a few friends for help and I keep getting mixed answers.

v = gt

98m/s = 9.8m/s * 10

Average V = initial v + final v

2

Average V = 0m/s + 98m/s

2

Average V=49m/s

Distance Traveled d = ½ gt squared

½ * 9.8m/s * 10 squared = 490m

or

Vf=Vo+at = 0msec+10msec2(10sec)= 100msec

AverageVelocity=Vf+Vo2=100ms+0ms2=50msec

X=Vot +12at2=0ms(10sec)+12(10msec2)(10sec)2=500 meters

Who's on the right path?

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# The instantaneous velocity of a freely falling object

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