The integral of the convolution between functions f

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The discussion revolves around proving that the integral of the convolution of two functions f and g equals the product of their integrals. A user seeks assistance and shares their approach using Fubini's theorem, demonstrating the steps leading to the conclusion. They clarify that a misunderstanding regarding variable translation affected their initial proof attempt. The conversation highlights the importance of recognizing the impact of integration domains on the value of integrals. Ultimately, the user expresses gratitude for the clarification received.
muzialis
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Hello there,

I am really struggling to prove that
"The integral of the convolution between functions f and gequals the product of their integrals", http://en.wikipedia.org/wiki/Convolution#Integration
Can anybody give me a hint?

Many thanks
 
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What did you try?? Where are you stuck?
 


∫{∫f(y)g(x-y)dy}dx = ∫f(y){∫g(y-x)dx}dy (Fubini)
= ∫f(y){∫g(u)du)}dy = ∫f(y)dy∫g(u)du
 


Thanks very muhc for your help.
I was following the line given by Mathman, but did not realize that the variable translation would not affcet the value of the integral as the integration domain is the whole real line, many thanks
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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