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thanks for reading.

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- #1

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thanks for reading.

- #2

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The Laplace transform of [tex] \int_0^t f(\tau) d\tau [/tex] is equal to [tex] \frac{1}{s} F(s) [/tex], where F(s) is the Laplace transform of f(t). Thus integration in the time domain is equal to multiplication by [tex] \frac{1}{s} [/tex] in the s-domain.

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(Another small question: how can you paste the formulas in the pages here? )

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