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The integration block in matlab

  1. Mar 5, 2007 #1
    I am new to matlab. There's a small thing that I am not aware of: why the integration block in simulink has the symbol as 1/s?
    thanks for reading.
     
  2. jcsd
  3. Mar 5, 2007 #2
    The Laplace transform of [tex] \int_0^t f(\tau) d\tau [/tex] is equal to [tex] \frac{1}{s} F(s) [/tex], where F(s) is the Laplace transform of f(t). Thus integration in the time domain is equal to multiplication by [tex] \frac{1}{s} [/tex] in the s-domain.
     
    Last edited: Mar 5, 2007
  4. Mar 6, 2007 #3
    Thank you las3riock. It's clear now.

    (Another small question: how can you paste the formulas in the pages here? )
     
  5. Mar 6, 2007 #4
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