1. Mar 5, 2007 #1

   pixel01

   

   I am new to matlab. There's a small thing that I am not aware of: why the integration block in simulink has the symbol as 1/s?
   thanks for reading.

    

   pixel01, Mar 5, 2007
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3. Mar 5, 2007 #2

   las3rjock

   

   The Laplace transform of [tex] \int_0^t f(\tau) d\tau [/tex] is equal to [tex] \frac{1}{s} F(s) [/tex], where F(s) is the Laplace transform of f(t). Thus integration in the time domain is equal to multiplication by [tex] \frac{1}{s} [/tex] in the s-domain.

    

   Last edited: Mar 5, 2007

   las3rjock, Mar 5, 2007
4. Mar 6, 2007 #3

   pixel01

   

   Thank you las3riock. It's clear now.
   
   (Another small question: how can you paste the formulas in the pages here? )

    

   pixel01, Mar 6, 2007
5. Mar 6, 2007 #4

   las3rjock

   

   Inclusion of mathematical formulas in posts is covered in this thread: https://www.physicsforums.com/showthread.php?t=8997

    

   las3rjock, Mar 6, 2007

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