# The integration block in matlab

1. Mar 5, 2007

### pixel01

I am new to matlab. There's a small thing that I am not aware of: why the integration block in simulink has the symbol as 1/s?

2. Mar 5, 2007

### las3rjock

The Laplace transform of $$\int_0^t f(\tau) d\tau$$ is equal to $$\frac{1}{s} F(s)$$, where F(s) is the Laplace transform of f(t). Thus integration in the time domain is equal to multiplication by $$\frac{1}{s}$$ in the s-domain.

Last edited: Mar 5, 2007
3. Mar 6, 2007

### pixel01

Thank you las3riock. It's clear now.

(Another small question: how can you paste the formulas in the pages here? )

4. Mar 6, 2007