The integration block in matlab

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  • Thread starter pixel01
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  • #1
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I am new to matlab. There's a small thing that I am not aware of: why the integration block in simulink has the symbol as 1/s?
thanks for reading.
 

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  • #2
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The Laplace transform of [tex] \int_0^t f(\tau) d\tau [/tex] is equal to [tex] \frac{1}{s} F(s) [/tex], where F(s) is the Laplace transform of f(t). Thus integration in the time domain is equal to multiplication by [tex] \frac{1}{s} [/tex] in the s-domain.
 
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  • #3
688
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Thank you las3riock. It's clear now.

(Another small question: how can you paste the formulas in the pages here? )
 
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