The kinetic energy formula for lagrange doesnt make sense

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SUMMARY

The discussion centers on the kinetic energy formula as applied to a pendulum, specifically addressing the confusion regarding the addition of kinetic energy components. The kinetic energy is defined by the equation T = 1/2 m v^2, where v represents the total velocity. The user initially misunderstands the relationship between the total kinetic energy and its components, mistakenly believing that T does not equal the sum of the kinetic energies of the x and y components. The resolution highlights that the squared nature of velocity allows for the addition of kinetic energy components, confirming that T(x) + T(y) correctly represents the total kinetic energy.

PREREQUISITES
  • Understanding of kinetic energy and the formula T = 1/2 m v^2
  • Basic knowledge of vector decomposition in physics
  • Familiarity with the concept of components of motion in two dimensions
  • Knowledge of the Pythagorean theorem as it applies to velocity components
NEXT STEPS
  • Explore the derivation of kinetic energy from basic principles of physics
  • Study vector decomposition techniques in physics for better understanding of motion
  • Learn about the implications of squaring velocity in kinetic energy calculations
  • Investigate the application of kinetic energy in different physical systems, such as pendulums and projectiles
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, educators teaching kinetic energy concepts, and anyone seeking to clarify the relationship between total and component kinetic energy.

grandpa2390
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Homework Statement


This is a real basic question I am sure. Maybe I just missed something.
so in the book, t = the kinetic energy . only for a pendulum, they add kinetic energy of x dot squared, plus kinetic energy of y dot squared.

Homework Equations


T = 1/2 m v^2
a^2 + b^2 = c^2

The Attempt at a Solution


This doesn't make sense. At first I thought maybe they were splitting velocity into x and y components.
but T(velocity) is not equal to T(x component of velocity) + T(y component of velocity). if I am traveling in a straight line at 5 m/s, 1/2m(5)^2 is not equal to 1/2m(3)^2 + 1/2m(4)^2. what is the xdot and ydot a measure of
 
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grandpa2390 said:
1/2m(5)^2 is not equal to 1/2m(3)^2 + 1/2m(4)^2
Are you a betting man?
 
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haruspex said:
Are you a betting man?
No I am not. And I get the feeling you are about to tell me that it's a good thing. lol because 3^2 +4^2 does equal 5^2 ... this is what I get for forcing myself out of bed to study... sry for the inconvenience. It made sense earlier when I was awake. Then I take a nap. force myself up, and I am writing a formula that says exactly what I said wasn't making sense. lol.

They only hope I have to hold onto is that my professor says that you aren't a physicist unless you occasionally write something stupid.

edit: I know what i was thinking. the variable itself v being plugged in, and then just replacing it with components added. x and y. 3 + 4 != 5 but i guess that's why v is squared in kinetic energy. so that the kinetic energy of components can be added. you can't say .5m(x+y)^2 but u can say the other
 
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