The length of a wire forming a solenoid

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SUMMARY

The discussion focuses on calculating the length of wire needed to form a solenoid with specific parameters. The solenoid is 1.33 m long, has a diameter of 0.0260 m, and carries a current of 17.8 A, resulting in a magnetic field of 22.4 mT. The key equation used is B = (Mu sub 0) * n * i, where Mu sub 0 is 4π x 10^(-7) (T*m)/A. By determining the number of turns (n) and the circumference of each turn, the total length of the wire can be accurately calculated.

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  • Understanding of solenoid physics and magnetic fields
  • Familiarity with the equation B = (Mu sub 0) * n * i
  • Knowledge of calculating circumference from diameter
  • Basic algebra for solving equations
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Kristen716
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I need help! I am unsure of what to do.

A solenoid 1.33 m long and 0.0260 m in diameter carries a current of 17.8 A. The magnetic field inside the solenoid is 22.4 mT. Find the length of the wire forming the solenoid.

The only information I have is the equation B=(Mu sub 0)*n*i
Where Mu sub 0=4*pi*10^(-7) (T*m)/A
 
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If you can find the number of turns (n), and you know the circumference of each turn (given), then you know the length of the wire.

- Warren
 
Thank You! I got the right answer!
 

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