The math involved in bending a rod

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    Bending Rod
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SUMMARY

The discussion focuses on calculating the length of a door lever prior to bending, specifically a lever with a 90-degree bend. Key parameters include an inner radius of 0.416 inches and an outer radius of 0.892 inches. The calculation involves determining the arc length of the outer radius using the formula for circumference, leading to an approximate total length of the lever as the sum of straight lengths and half the circumference of the average radius. The discussion emphasizes the importance of material properties, particularly for brass, which affects stretching and compression during the bending process.

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  • Understanding of basic geometry, specifically arc length calculations
  • Familiarity with material properties, particularly stretching and compression
  • Knowledge of SolidWorks for modeling and simulation
  • Basic engineering principles related to bending and fabrication
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  • Research "arc length calculations for circular segments" to refine bending calculations
  • Study "material properties of brass" to understand its behavior under bending
  • Learn "SolidWorks bending simulation techniques" for accurate modeling
  • Explore "reverse engineering techniques in mechanical design" for practical applications
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Mechanical engineers, product designers, and anyone involved in the fabrication and modeling of bent metal components will benefit from this discussion.

camacru
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I have a door lever which has a 90 deg. bend. I need to calculate the length that this lever would have to be if it were in the form of a straight rod, prior to being bent.

I know I have all the input data, I'm just not sure how to express this algebraically. For example, I know that the inner radius of the bend is 0.416", and the outer radius is 0.892". Based on this data, how can I calculate the length of the lever prior to being bent?

Thanks in advance!
 
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That would depend on how much the rod material can stretch and/or compress. Assuming no stretching, then the outer radius would consist of a quarter-circle having the same radius (0.892"). That arc would then have a length of 1/4 of the circumference of a 0.892" radius circle. Calculate that then add the straight lengths to it.

C=2\pi r

\frac{1}{4}C=\frac{\pi r}{2}

If the material stretches, this won't be accurate though.

It would be much easier to take a piece of rod of a known length, bend it, and cut off the amount you don't need. Subtract that amount (that was cut off) from your original length. That will give you the total length needed.
 
It is a nontrivial engineering problem and the answer will depend on properties of the material.

To the lowest approximation, it would probably be most accurate to assume that the outer half of the rod will stretch and the inner half will compress. So, the total length ~ straight lengths + pi r_c/2 where r_c = (0.416+0.892)/2.

My advice would be to do this experimentally, as the previous poster suggested.
 
Thanks for the help guys. The lever is actually made out of brass, so there is definitely some degree of stretching and compression. Here's the problem. Basically, what I am doing is a simple exercise in reverse engineering. I have a finished lever sample, and I am trying to duplicate it in Solidworks, but I need to model it in the form of a straight rod because it will be lathed then bent. I modeled the lever, applied a flex modifier and bent the digital rod to 90deg. However, when I supplied the drawings to the shop, the bend was completely off. Perhaps the problem is as simple as not having used the proper bending wheel during the bending process. Nonetheless, I want to re-evaluate my design, and mathematically calculate the dimensions to determine if my model was flawed to begin with. Do you think this can be done without having the exact physical properties of the material?
 

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