The motion of a particle in the central force

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SUMMARY

The discussion focuses on demonstrating that the motion of a particle under a central force defined by F = -kr results in an elliptical orbit. The equations of motion are derived as m d²x/dt² = -kx and m d²y/dt² = -ky, leading to the solutions x = Acos(ωt + βx) and y = Bsin(ωt + βy). The phase constants βx and βy are assumed to be zero for simplification, which is a valid approach for analyzing the system's motion.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Familiarity with harmonic motion equations
  • Knowledge of elliptical orbits in classical mechanics
  • Basic proficiency in solving differential equations
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  • Study the derivation of elliptical orbits in classical mechanics
  • Learn about the implications of central forces on particle motion
  • Explore the role of phase constants in oscillatory motion
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Students of physics, particularly those studying classical mechanics, as well as educators and anyone interested in the mathematical modeling of particle motion under central forces.

GeoStudy

Homework Statement



I just need a hint. So we are given:

F = -kr

We are asked:

Show that:

(a) The orbit is an ellipse with the force center at the center of the ellipse.

Homework Equations



I guess we break it up into its components:

The Attempt at a Solution



m d2x/dt2 = -kx => x = Acos(ωt + βx)

m d2y/dt2 = -ky => y= Bsin(ωt + βy)

where βx = βy = 0
 
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GeoStudy said:

Homework Statement



I just need a hint. So we are given:

F = -kr

We are asked:

Show that:

(a) The orbit is an ellipse with the force center at the center of the ellipse.

Homework Equations



I guess we break it up into its components:

The Attempt at a Solution



m d2x/dt2 = -kx => x = Acos(ωt + βx)

m d2y/dt2 = -ky => y= Bsin(ωt + βy)

where βx = βy = 0
Yes, except why assume the phase constants are zero?
 

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