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The only 3 consecutive odd numbers that are primes are 3,5,7

  1. Oct 28, 2009 #1
    1. The problem statement, all variables and given/known data
    Show that the only three consecutive numbers that are primes are 3,5,7.


    2. Relevant equations



    3. The attempt at a solution
    let p, p+2, p+4 be three consecutive odd numbers
    If p=0(mod3), p is divisible by 3
    If p=1(mod 3), p+2 is divisible by 3
    If p=2(mod3), p+4 is divisible by 3

    This means at least one of p, p+2, p+4 is divisible by 3

    Since we are looking for prime numbers 3 can be the only number that is divisible by 3. Therefore we only have 3 possible solutions:

    -1,1,3
    1,3,5
    3,5,7

    Since -1 and 1 are not primes the only possible solution is 3,5,7


    -I no i have the solution here, its just i was helped with this and i dont quite understand why we bring in (mod3) is that just the way it is done or why do you include it??
     
  2. jcsd
  3. Oct 28, 2009 #2
    One way of proving that a number (or at least one of 3 numbers) isn't prime, is proving that it is divisible by another prime. We know the numbers are odd, so 3 is the next candidate.

    One way of proving a result concerning divisibility by a particular number, is to consider all cases modulo that number, in this case p=0,1,2 (mod 3).
     
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