The PDF of the exponential of a Gaussian random variable

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The discussion focuses on determining the probability density function (PDF) of the exponential of a Gaussian random variable. It presents the transformation Y = exp(αX), where X follows a Gaussian distribution, and derives the PDF using the Dirac delta function. Participants explore the relationship between this PDF and the log-normal distribution, noting that the transformation requires careful consideration of the Jacobian. Questions arise regarding the conditions under which the derived expressions are valid, particularly in relation to the constant y in the integral. The conversation emphasizes the importance of correctly applying transformation techniques in probability theory.
samuelandjw
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What is the PDF of the exponential of a Gaussian random variable?

i.e. suppose W is a random variable drawn from a Gaussian distribution, then what is the random distribution of exp(W)?

Thank you!
 
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The PDF for:
<br /> Y = \exp{\left(\alpha \, X\right)}<br />
where the PDF for X is:
<br /> \varphi_{X}(x) = \frac{1}{\sqrt{2 \, \pi} \, \sigma} \, e^{-\frac{(x - a)^{2}}{2 \, \sigma^{2}}}<br />
is given by:
<br /> \varphi_{Y}(y) = \int_{-\infty}^{\infty}{\delta(y - \exp(\alpha \, x)) \, \varphi_{X}(x) \, dx}<br />

Use the properties of the Dirac delta function to evaluate this integral exactly!
 
Dickfore said:
The PDF for:
<br /> Y = \exp{\left(\alpha \, X\right)}<br />
where the PDF for X is:
<br /> \varphi_{X}(x) = \frac{1}{\sqrt{2 \, \pi} \, \sigma} \, e^{-\frac{(x - a)^{2}}{2 \, \sigma^{2}}}<br />
is given by:
<br /> \varphi_{Y}(y) = \int_{-\infty}^{\infty}{\delta(y - \exp(\alpha \, x)) \, \varphi_{X}(x) \, dx}<br />

Use the properties of the Dirac delta function to evaluate this integral exactly!

Thank you, Dickfore.

I realize I can just use <br /> \varphi_{Y}(y)=\varphi_{X}(x) \frac{dx}{dy}<br />
and the result is almost log-normal distribution pdf, but your method looks quite interesting.

I do have a question, in your last integral, suppose y is constant in the integral, then the result would be \varphi_{Y}(y)=\varphi_{X}(x=\frac{1}{\alpha}\ln{y}), which is not quite the same as the log-normal. I'm not sure if I have gotten it wrong.
 
you had forgotten the Jacobian of the transofrmation:
<br /> \left|\frac{d x}{d y}\right|<br />
expressed as a function of y. For what values of y do the above expressions make sense?
 
Dickfore said:
you had forgotten the Jacobian of the transofrmation:
<br /> \left|\frac{d x}{d y}\right|<br />
expressed as a function of y. For what values of y do the above expressions make sense?

Thx.
 
First trick I learned this one a long time ago and have used it to entertain and amuse young kids. Ask your friend to write down a three-digit number without showing it to you. Then ask him or her to rearrange the digits to form a new three-digit number. After that, write whichever is the larger number above the other number, and then subtract the smaller from the larger, making sure that you don't see any of the numbers. Then ask the young "victim" to tell you any two of the digits of the...

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