The PDF of the exponential of a Gaussian random variable

Click For Summary

Discussion Overview

The discussion centers on determining the probability density function (PDF) of the exponential of a Gaussian random variable. Participants explore the mathematical formulation and properties of this transformation, including the use of the Dirac delta function and Jacobian transformations.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant asks for the PDF of the random variable Y = exp(W), where W is drawn from a Gaussian distribution.
  • Another participant provides a mathematical expression for the PDF of Y using the Dirac delta function and suggests evaluating the integral to find the PDF.
  • A different participant acknowledges the provided method but raises a question about the relationship between the derived PDF and the log-normal distribution, suggesting a potential misunderstanding in the transformation process.
  • Several participants emphasize the importance of including the Jacobian of the transformation in the calculations and inquire about the conditions under which the expressions hold true.

Areas of Agreement / Disagreement

Participants express differing views on the transformation process and the implications for the resulting distribution, indicating that the discussion remains unresolved with multiple competing perspectives on the correct approach.

Contextual Notes

There are limitations regarding the assumptions made in the transformation process, particularly concerning the Jacobian and the conditions for the validity of the derived expressions.

samuelandjw
Messages
22
Reaction score
0
What is the PDF of the exponential of a Gaussian random variable?

i.e. suppose W is a random variable drawn from a Gaussian distribution, then what is the random distribution of exp(W)?

Thank you!
 
Physics news on Phys.org
The PDF for:
<br /> Y = \exp{\left(\alpha \, X\right)}<br />
where the PDF for X is:
<br /> \varphi_{X}(x) = \frac{1}{\sqrt{2 \, \pi} \, \sigma} \, e^{-\frac{(x - a)^{2}}{2 \, \sigma^{2}}}<br />
is given by:
<br /> \varphi_{Y}(y) = \int_{-\infty}^{\infty}{\delta(y - \exp(\alpha \, x)) \, \varphi_{X}(x) \, dx}<br />

Use the properties of the Dirac delta function to evaluate this integral exactly!
 
Dickfore said:
The PDF for:
<br /> Y = \exp{\left(\alpha \, X\right)}<br />
where the PDF for X is:
<br /> \varphi_{X}(x) = \frac{1}{\sqrt{2 \, \pi} \, \sigma} \, e^{-\frac{(x - a)^{2}}{2 \, \sigma^{2}}}<br />
is given by:
<br /> \varphi_{Y}(y) = \int_{-\infty}^{\infty}{\delta(y - \exp(\alpha \, x)) \, \varphi_{X}(x) \, dx}<br />

Use the properties of the Dirac delta function to evaluate this integral exactly!

Thank you, Dickfore.

I realize I can just use <br /> \varphi_{Y}(y)=\varphi_{X}(x) \frac{dx}{dy}<br />
and the result is almost log-normal distribution pdf, but your method looks quite interesting.

I do have a question, in your last integral, suppose y is constant in the integral, then the result would be \varphi_{Y}(y)=\varphi_{X}(x=\frac{1}{\alpha}\ln{y}), which is not quite the same as the log-normal. I'm not sure if I have gotten it wrong.
 
you had forgotten the Jacobian of the transofrmation:
<br /> \left|\frac{d x}{d y}\right|<br />
expressed as a function of y. For what values of y do the above expressions make sense?
 
Dickfore said:
you had forgotten the Jacobian of the transofrmation:
<br /> \left|\frac{d x}{d y}\right|<br />
expressed as a function of y. For what values of y do the above expressions make sense?

Thx.
 

Similar threads

  • · Replies 30 ·
2
Replies
30
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
4
Views
3K
  • · Replies 9 ·
Replies
9
Views
5K