The pressure sand exerts on a particular area.

  • Thread starter Thread starter Physics321
  • Start date Start date
  • Tags Tags
    Area Pressure
Click For Summary
SUMMARY

The discussion focuses on calculating the pressure exerted by falling sand grains on a surface. Each grain has a mass of 3.0x10^-3 g and falls from a height of 0.8 m at a rate of 50 grains per second per cm². The pressure can be determined using the formula P = F/A, where F is the force calculated from the mass and acceleration due to gravity, and A is the area in SI units, specifically 0.0001 m² for accurate calculations. The participants emphasize the importance of using the correct units and applying the fundamental physics equations correctly.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Knowledge of pressure calculation (P = F/A)
  • Familiarity with SI units and unit conversions
  • Basic principles of kinematics related to falling objects
NEXT STEPS
  • Research the derivation of the pressure formula P = F/A
  • Study the effects of gravitational acceleration on falling objects
  • Learn about unit conversions in physics, particularly for mass and area
  • Explore the concept of momentum and its relation to force over time
USEFUL FOR

Physics students, educators, and anyone interested in understanding the dynamics of pressure and force in relation to falling objects.

Physics321
Messages
12
Reaction score
0
Grains of sand of mass 3.0x10^-3 g each, fall from a height of 0.8 m on a sticky surface at a rate of 50 grains per second per cm^2. What pressure does this shower of sand exert on the surface, assuming that air resistance can be neglected?

I'm really not sure what angle to take here. I believe they are trying to get me to use the equation P=F/A, however, F=ma? and F/A=mv^2(N/V).

Am I suppose to treat this problem like an ideal gas, because the sand particles are so light?

In addition, should i use 0.0001 m^2 for the area since it is SI units?
 
Physics news on Phys.org
Hi Physics321! :smile:

Use the full form of F = ma … F = d/dt (mv) …

how much mv is changing per second? :wink:
 

Similar threads

  • · Replies 23 ·
Replies
23
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
6
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
18K
  • · Replies 15 ·
Replies
15
Views
3K
Replies
28
Views
6K
  • · Replies 24 ·
Replies
24
Views
3K