The Roche Limit Formula: Discover the Solution to This Celestial Phenomenon

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SUMMARY

The Roche Limit formula is defined as RL = 2.423Rp(dp/dm)^(1/3), where RL represents the Roche Limit, Rp is the radius of the planet, dp is the density of the planet, and dm is the density of the moon. In cases where the moon and planet have equal densities, the formula simplifies to RL = 2.423Rp. This formula is crucial for understanding the gravitational interactions between celestial bodies and their potential for tidal disruption.

PREREQUISITES
  • Understanding of gravitational forces in celestial mechanics
  • Familiarity with basic physics concepts related to density
  • Knowledge of mathematical operations involving exponents
  • Awareness of celestial body characteristics, such as radius and density
NEXT STEPS
  • Research the implications of the Roche Limit in planetary science
  • Explore tidal forces and their effects on moons and planets
  • Learn about the densities of various celestial bodies
  • Investigate other formulas related to gravitational interactions
USEFUL FOR

Astronomers, astrophysicists, and students studying celestial mechanics will benefit from this discussion, particularly those interested in the dynamics of moons and planets.

Slatiebartfarce
[SOLVED] The Roche Limit

What's hte formula for the Roche Limit? I can't find it any where!
 
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RL = 2.423Rp(dp/dm)1/3

where

RL is the Roche Limit
Rp is the radius of the planet
dp is the density of the planet
dm is the density of the moon.

if the moon and planet are of equal density, it reduces to

RL = 2.423Rp
 
thanks

Thanks for that
 

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