The Simpsons mathematic geek received no attention

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LukeD said:
If x is positive, then [itex]x^{1/n}[/itex] is the unique positive number y such that [itex]y^n = x[/itex]. If x is negative and n is odd, then [itex]x^{1/n}[/itex] is the unique negative number y such that [itex]y^n=x[/itex]. If x is negative and n is even, then [itex]x^{1/n}[/itex] is [itex]i(-x)^{1/n}[/itex]
This is usually where I fall out.
Too complicated relative to what I find interesting and relevant at the moment (and usually in general)
I've had a problem with this at school and in other situations as well.
I'm somehow not able to participate in other peoples thinking within specific subjects.
I guess this is one of my social lacks.
I'd probably understand it if I sat down; putting my mind into it, but I'll never be able to do that, since I rather sit down, putting my mind into Perl if I one day had some spare energy (this, because it's easier to earn money on some Perl skills, than some general math, and I'm in deep need of money without having to walk outside, or basically do something I'm interested in while earning money)
OK, this went OT again.
Point is that I got a problem understanding it "this way".
It's easier if you add examples of numbers to make it practical, in addition.

Thanks for your understanding, patience and everything else :)
 
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