The sum of elastic and gravitational energy

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SUMMARY

The discussion revolves around calculating gravitational energy, kinetic energy, and the sum of elastic and gravitational energy for a 20kg ball on a trampoline. The gravitational energy at the apex is calculated as 400J using the formula Eg = mgh. The kinetic energy just before impact is also 400J, indicating energy conservation. The participants highlight that the sum of elastic and gravitational energy at maximum stretch can be determined using energy conservation principles, although some confusion exists regarding the approach to this calculation.

PREREQUISITES
  • Understanding of gravitational potential energy (Eg = mgh)
  • Knowledge of kinetic energy (Ek = 1/2 mv²)
  • Familiarity with the law of conservation of energy
  • Basic concepts of elastic potential energy
NEXT STEPS
  • Study the work-energy theorem and its applications
  • Learn about elastic potential energy and its calculations
  • Explore energy conservation in oscillatory systems
  • Review examples of energy transformations in mechanical systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy conservation principles, as well as educators looking for practical examples of energy transformations.

buonastella
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Homework Statement


1. What is the gravitational energy (relative to the unstretched surface of the trampoline) of the 20kg ball at its apex 2.0m above the trampoline
2. What is the kinetic energy of the ball just before impacting the trampoline
3. At maximum stretch at the bottom of the motion, what is the sum of elastic and gravitational energy of the ball?
4. What conclusions can you draw for the answers above

Homework Equations


I think I've got them all right except 3 in which I am not sure how to approach it

The Attempt at a Solution


1. Eg = mgh = 392J
sig digs make it 400J

2. All energy is transferred into kinetic energy therefore
Ek = 400J

3. ? Like what I've got is mg(2 +x) but like I'm not sure if I'm approaching it correctly

4. Through the answers above, I can conclude that energy is always conserved through the law of conservation of energy
 
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I think there is some part of the problem statement missing.
(3) can be solved with energy conservation alone.
 
mfb said:
I think there is some part of the problem statement missing.
(3) can be solved with energy conservation alone.
What do you mean?
 
buonastella said:
3. ? Like what I've got is mg(2 +x) but like I'm not sure if I'm approaching it correctly
Hint : What is the KE of the object at maximum stretch ? What was it initially ? What does the work - energy theorem state ?
 
buonastella said:
what I've got is mg(2 +x)
That's the loss in PE, but that's not what you are asked for.
Bear in mind that you are taking the zero PE level as the unstretched trampoline height. In that frame, you started with 400J. Where has all that gone when at bottom of bounce?
buonastella said:
I can conclude that energy is always conserved
No, you cannot conclude that. You assumed that in order to answer the questions.
 

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