MHB The two values for $\theta$ would be 0 and $\pi$.

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The area enclosed by the lemniscate defined by r² = -25cos(θ) is calculated to be 25. To find the correct integral setup, the interval of integration must be determined, specifically the values of θ that return to the origin. The two values for θ that achieve this within the interval [0, 2π) are 0 and π. Understanding these values is crucial for setting up the integral correctly to compute the area. The discussion emphasizes the importance of identifying the appropriate limits for integration in polar coordinates.
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Question: What is the area enclosed by the lemniscate r2 = -25cos(Ѳ)?
The answer is 25.

I can't seem to set up the integral for this question correctly. I know that the area enclosed by a polar curve is obtained by the integral(r2/2) dѲ, but I can't determine what the interval of integration would be.
Help please!
 
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Let's take a look at a plot of the curve:

View attachment 2452

We want to begin and end at the origin...what two values for $\theta$ on $[0,2\pi)$ will put you at the origin?
 

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