The velocity and acceleration of particle give position vector

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SUMMARY

The position vector of a particle is defined as s = e-2ti + sin(2t)j + 5tk. To calculate the velocity at t=0, the first derivative with respect to time t yields a velocity of -2i + 2j. For acceleration, the second derivative must be computed; initially, an error occurred in differentiating the k component, but the correct acceleration at t=0 is determined to be 4i + 10k.

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jake241190
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the position vector of the particle is given by

s=e^-2ti+sin(2t)j+5t^k

calculate its velocity and acceleration at t=0
to get the velocity i differentiated with respect to t and substituted in t=0, giving me

velocity=-2i+2j and that's the same as the answer given but I am not sure how to get the acceleration i tried differentiating again and got a answer
acceleration= 4i+0i+0k and this isn't correct
 
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never mind i know what I've don i forgot to differentite the k bit the second time giving
acceleration= 4i+10k
 

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