The velocity and acceleration of particle give position vector

[jake241190]

the position vector of the particle is given by

s=e^-2ti+sin(2t)j+5t^k

calculate its velocity and acceleration at t=0
to get the velocity i differentiated with respect to t and substituted in t=0, giving me

velocity=-2i+2j and that's the same as the answer given but I am not sure how to get the acceleration i tried differentiating again and got a answer
acceleration= 4i+0i+0k and this isn't correct

 

[jake241190]

never mind i know what I've don i forgot to differentite the k bit the second time giving
acceleration= 4i+10k