How Does Speaker Placement Affect Sound Frequency Detection?

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SUMMARY

The discussion focuses on calculating the possible frequencies produced by two speakers placed 4.0 meters apart, with a student observing a quiet spot at a distance of 2.0 meters from one speaker and 2.3 meters from the other. The speed of sound in the room is given as 350 m/s. The relevant equation used is the path difference (PD) equation, PD = (n-1/2) λ, leading to the frequency calculation f = v/λ. The initial attempt at the solution was incorrect, highlighting the importance of careful calculations in determining the correct denominator.

PREREQUISITES
  • Understanding of sound wave properties and frequency calculations
  • Familiarity with the concept of path difference in wave interference
  • Basic knowledge of wavelength and its relationship to frequency
  • Proficiency in algebraic manipulation of equations
NEXT STEPS
  • Study the principles of wave interference and sound wave behavior
  • Learn how to apply the path difference formula in various scenarios
  • Explore the relationship between frequency, wavelength, and speed of sound
  • Practice solving problems involving multiple sound sources and their effects
USEFUL FOR

Students in physics or acoustics, educators teaching sound wave concepts, and anyone interested in the practical applications of sound frequency detection in real-world scenarios.

Arnoldjavs3
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Hi I am having a rough time with this questoin .

Homework Statement


Question: A student enters Best Buy prepared to buy a pair of speakers. Before he does so, he conducts an experiment with them. He places the speakers 4.0 m apart and connects a signal generator to both speakers that produces a single and consistent tone. (constant wavelength and frequency) He then walks to a point that is 2.0 m from one speaker and 2.3 m from the other. At that point he notices a quiet “spot”. If the speed of the sound in the room is known to be 350 m/s, calculate the possible frequencies being played by the speakers.



Homework Equations


PD = (n-1/2) λ



The Attempt at a Solution


f = v/(lambda) = 350/6(2n + 1) = 58.33/(2n+1) ... n belongs to integer
 
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Arnoldjavs3 said:
350/6(2n + 1)
That denominator is not right. Try again. Take more care.
 
PD = (n-1/2) λ ... PD = 0.3
 

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