Thank you!skeeter said:$W_{net} = [22\cos(40) - 12]\cdot 5 = \dfrac{1}{2} \cdot 25 \cdot v_f^2 \implies v_f = 1.39 \, m/s$
The work-energy principle states that the work done on an object is equal to the change in its kinetic energy. This means that the amount of work done on an object will result in a change in its speed or direction.
Work is calculated by multiplying the force applied to an object by the distance it moves in the direction of the force. This can be represented by the equation W = Fd, where W is work, F is force, and d is distance.
Work and energy are closely related, as work is the transfer of energy from one form to another. When work is done on an object, energy is either added or removed from the object, resulting in a change in its energy state.
Power is the rate at which work is done or energy is transferred. It is calculated by dividing the work done by the time it takes to do the work. This means that the more work is done in a shorter amount of time, the greater the power.
Yes, the work-energy principle can be applied to all forms of energy, including kinetic, potential, thermal, and electrical energy. This is because all forms of energy can be converted into work or vice versa.