Theoretical question on cyclic function

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nhrock3
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a(x) is continues on R with cycle T ,a(x+T)=a(x)
u(x) is non trivial soluion of y'=a(x)y
[tex]\lambda=\int_{0}^{T}a(x)dx[/tex]

which of the following claims is correct:

A. if [tex]\lambda>0[/tex] then [tex]\lim_{x\rightarrow\infty}u(x)=\infty[/tex]
B. if [tex]\lambda=0[/tex] then u(x) is a cyclic function

i don't have the theorectical basis to solve it
 
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The equation is separable. Write it as

[tex]\frac{y'}{y} = a(x)[/tex]

and integrate both sides over one period.
 
how to integrate over a cycle
?
what to do after i integrate over a cycle
[tex]\int\frac{dy}{y}=\int a(x)dx[/tex]

[tex]\ln y=\inta(x)dx[/tex]
 
nhrock3 said:
how to integrate over a cycle
?
what to do after i integrate over a cycle
[tex]\int\frac{dy}{y}=\int a(x)dx[/tex]

[tex]\ln y=\inta(x)dx[/tex]

Try

[tex]\int_{u(0)}^{u(T)}\frac{dy}{y}=\int_0^T a(x)dx[/tex]