Theoretical question on solutions

  • Thread starter nhrock3
  • Start date
  • Tags
    Theoretical
In summary, we have a differential equation y'=f(x)y+g(x) on (a,b), with a specific point x_0 where g(x_0) differs from zero. If u_1 and u_2 are both solutions to the equation on (a,b), and for some c and d, d*u_1+c*u_2 is also a solution, then we can conclude that either c or d is equal to zero. Alternatively, c=1-d or c^2+d^2=1. This information also suggests that there could be a single solution for the initial condition on (a,b).
  • #1
nhrock3
415
0
we have y'=f(x)y+g(x) when f and g are continues on (a,b).
and there is a point x_0 for which g(x_0) differs zero.suppose that u_1 and u_2 are
solution to the equation on (a,b) .and if for some c,d d*u_1+c*u_2 is also a solution
thn we cn conclude that : (we need to choose one of the options)
A. c or d is zero
B. c=1-d
C. c^2+d^2=1
D.if u_1 and u_2 are
solution to the equation then d*u_1+c*u_2 is also a solution


i only know that on (a,b) there could be a single solution for the initial condition.
thats my theoretical knowledge on the subject
 
Physics news on Phys.org
  • #2
nhrock3 said:
we have y'=f(x)y+g(x) when f and g are continues on (a,b).
and there is a point x_0 for which g(x_0) differs zero.suppose that u_1 and u_2 are
solution to the equation on (a,b) .and if for some c,d d*u_1+c*u_2 is also a solution
thn we cn conclude that : (we need to choose one of the options)
A. c or d is zero
B. c=1-d
C. c^2+d^2=1
D.if u_1 and u_2 are
solution to the equation then d*u_1+c*u_2 is also a solution


i only know that on (a,b) there could be a single solution for the initial condition.
thats my theoretical knowledge on the subject

Start working with your given information. For example, since u1 and u2 are solutions to the diff. equation, then
u1'(x) = f(x)u1(x) + g(x), and
u2'(x) = f(x)u2(x) + g(x).

It also says that for some c and d, cu1 + du2 is a solution. What does that mean in terms of the given differential equation?
 

1. What is a theoretical solution?

A theoretical solution is a proposed solution to a problem that has not yet been tested or proven to be effective. It is based on existing knowledge and theories, but has not been put into practice.

2. How is a theoretical solution different from an experimental solution?

A theoretical solution is based on existing knowledge and theories, while an experimental solution is based on testing and collecting data to determine its effectiveness. A theoretical solution is more hypothetical and unproven, while an experimental solution has been tested and proven to some extent.

3. Can a theoretical solution become a practical solution?

Yes, a theoretical solution can become a practical solution if it is tested and proven to be effective through experimentation. However, not all theoretical solutions are able to be put into practice.

4. What are the benefits of considering theoretical solutions?

Considering theoretical solutions allows for creative and innovative thinking, as well as exploring new ideas. It also helps to develop a better understanding of the problem and potential solutions.

5. Are theoretical solutions always accurate?

No, theoretical solutions are not always accurate. They are based on existing knowledge and theories, which can sometimes be incorrect or incomplete. That is why experimentation and testing are important in determining the effectiveness of a theoretical solution.

Similar threads

  • Calculus and Beyond Homework Help
Replies
2
Views
365
  • Calculus and Beyond Homework Help
Replies
2
Views
746
  • Calculus and Beyond Homework Help
Replies
14
Views
392
  • Calculus and Beyond Homework Help
Replies
6
Views
1K
  • Calculus and Beyond Homework Help
Replies
8
Views
1K
  • Calculus and Beyond Homework Help
Replies
14
Views
2K
  • Calculus and Beyond Homework Help
Replies
3
Views
3K
  • Calculus and Beyond Homework Help
Replies
2
Views
886
  • Calculus and Beyond Homework Help
Replies
3
Views
955
  • Calculus and Beyond Homework Help
Replies
8
Views
1K
Back
Top