Math Challenge - October 2018

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  • #71
benorin
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The entire thing is positive, continuous and bounded, so Fubini applies.
^This.
That is what I should have answered to the Q: "Justify the initial equality by which theorem?" Except for at the origin, a singlet of measure zero. But that the integrand was unbounded thereat seemed to justify a little caution on my part; that and not knowing which Fubini Theorem variant to use. But then you both are experts, @fresh_42 strikes me as a seasoned Analysis prof, or the equivalent in terms of wit.
 
  • #72
benorin
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@fresh_42 added 7. e) to post #63 (done)
 

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