MHB Therefore, the roots of the given equation are $x=-4$ and $x=2$.

AI Thread Summary
The equation (x+3)^2 = 4x + 17 is solved by first expanding and rearranging it to x^2 + 2x - 8 = 0. The correct factorization of this quadratic yields (x+4)(x-2) = 0, leading to the roots x = -4 and x = 2. A common mistake was misidentifying the signs of the roots during the factoring process. The discussion emphasizes the importance of careful sign management in solving quadratic equations. Ultimately, the roots of the equation are confirmed as x = -4 and x = 2.
led
Messages
1
Reaction score
0
Solve (x+3)^2 = 4x+17 where did i go wrong?
(x+3)(x+3 )= 4x+17

x^2 + 3x + 3x + 9 = 4x+17

x^2 + 6x + 9 = 4x + 17

x^2 + 6x + 9 - 4x - 17 = 0

x^2 + 2x - 8 = 0

(x-2)(x+4) <-- USING THE CROSS METHOD View attachment 3985

x= -2, 4 is my cross method working incorrect or something? do explain my mistake
 

Attachments

  • math.png
    math.png
    7.3 KB · Views: 92
Mathematics news on Phys.org
led said:
where did i go wrong?
In the very last line. Well, second last line.
 
You have factored correctly, but your roots have the wrong signs.

Another method to solve this equation would be to write it as:

$$(x+3)^2-4x-17=0$$

$$(x+3)^2-4(x+3)-5=0$$

Now factor the quadratic in $x+3$:

$$\left((x+3)+1\right)\left((x+3)-5\right)=0$$

Combine like terms:

$$(x+4)(x-2)=0$$

Now, to find the actual roots, use the zero-factor property, and equate each factor to zero in turn and solve for $x$:

$$x+4=0\implies x=-4$$

$$x-2=0\implies x=2$$
 
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...

Similar threads

Replies
7
Views
1K
Replies
10
Views
2K
Replies
4
Views
1K
Replies
8
Views
1K
Replies
6
Views
2K
Replies
2
Views
1K
Back
Top