(Thermal Conductivity Question) Need Help

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Homework Help Overview

The discussion revolves around a thermal conductivity problem involving a glass window with specified temperatures, thickness, and thermal conductivity. Participants are examining how to calculate heat loss and the temperature of the outer surface under different conditions.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the thermal conductivity formula and the relationship between heat transfer and temperature difference. Questions arise regarding the interpretation of variables and the validity of calculations presented.

Discussion Status

Some guidance has been offered regarding the formula for heat transfer, but there is no consensus on the correctness of the calculations or the interpretation of the variables involved. Participants are exploring different aspects of the problem, with some seeking clarification on the second part of the question.

Contextual Notes

Participants are reminded that complete solutions cannot be provided, and there is an emphasis on understanding the underlying principles rather than simply applying formulas. The discussion includes questioning the assumptions made in the calculations and the relevance of the time factor in the second part of the problem.

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Homework Statement



1) The inner and outer surfaces of a glass window of area 2.5 m2 are at 22 ºC and 0 ºC respectively. What is the heat lost in 1 second if the glass is 5mm thick and has a thermal conductivity of 1.1 Wm^-1K^-1 ?

2) The same sheet of glass as described in the [above Question] is used as a window in a room at 23 ºC when the general outside temperature is -14 ºC. If the inner and outer heat transfer coefficients are both 17.0 Wm^-2K^-1, what is the temperature of the outside surface of the glass?

Can Anyone help me solve these two questions, Please? (with the formula used)

:)
 
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Hi MoZeS, welcome to PF.

You have given the thermal conductivity and note that there is a unit: W/(m K)
So what does the thermal conductivity express?
 
dQ/dt=kA(d theta/dx)
given,A=2.5m^2, x=5mm, k=1.1 Wm^-1K^-1
dQ/dt=kA(final temp-initial temp.)/x
=(1.1)(2.5)(22)/(5x10^-3)
=1.21x10^4W
Q=1.21x10^4J since, Q/t=1.21x10^4W
Q=1.21x10^4W/1s
therefore W/s = J
part 2, try on ur own ...
is same formulae...
dQ/dt=1.21x10^4W
so, subst. in the equation and find the final temp.
 
Welcome to PF lyming.
Please note that we don't give out complete solutions here at PF. Moreover, I don't really see what formula you are using (what is theta?) and how you are getting Q from dQ/dt. Also, there must be some mathematical errors, because I happen to know that W = J / s while you write W/s = J.

Finally, I think no looked up formula is needed at all and one can infer the answer by simply looking at the units of the given conductivity.
 
I see this one's been dead a while, but if someone want to help me out here...
I get the first part, but I'm struggling on the second one.
Do I still need to use the 1 second? And how to do I change the heat flow to temperature? Or is there a delta Temp used to solve this part?
 

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