Thermal Conductivity - Estimate Temperature

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SUMMARY

The discussion focuses on estimating the inner surface temperature of an insulating case with an outer surface temperature of 25°C, radiating heat to an environment at 20°C. The heat conduction through a thickness of 2.5mm with a temperature difference of 5°C leads to a calculated flux of J = 40 using thermal conductivity k = 0.02. Applying Stefan's Law, the correct inner surface temperature is determined to be approximately 26.8°C. This calculation clarifies the relationship between temperature gradients and heat flux in thermal systems.

PREREQUISITES
  • Understanding of thermal conductivity and its units
  • Familiarity with Stefan-Boltzmann Law
  • Knowledge of heat transfer principles
  • Basic calculus for temperature gradient calculations
NEXT STEPS
  • Study the derivation and applications of Stefan-Boltzmann Law
  • Explore thermal conductivity measurements and their significance
  • Learn about heat transfer in insulating materials
  • Investigate temperature gradient calculations in multi-layer systems
USEFUL FOR

Students in thermal physics, engineers working with insulation materials, and professionals involved in heat transfer analysis will benefit from this discussion.

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Homework Statement



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Given an insulating case outer surface at 25C, radiates heat to surroundings at 20C. Find temperature inner surface.

Homework Equations





The Attempt at a Solution



The heat is conducted through a thickness of 2.5mm, with a temperature difference of 5oC. Thus ##\frac{\partial T}{\partial z} = 2000##. Using ##k = 0.02##:

We have a value for the flux:

J = k\frac{\partial T}{\partial z} = 40

Using Stefan's Law:

J = \sigma T^4

We get ##T = 163K##, and boy that is one cold case!(-110oC)
 
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You seem to think the 5oC difference is between the iPod and the outside of the case.
Looks to me as if that temperature difference is to be calculated from the flux.
Stefan's law works two ways: 25 to 20 should be something like J = \sigma \left ( T_{\rm case}^4 - T_{\rm environment}^4 \right )
 
BvU said:
You seem to think the 5oC difference is between the iPod and the outside of the case.
Looks to me as if that temperature difference is to be calculated from the flux.
Stefan's law works two ways: 25 to 20 should be something like J = \sigma \left ( T_{\rm case}^4 - T_{\rm environment}^4 \right )

That's right, because ##J## is the net flux (caused by a temperature gradient). The answer turns out to be ##26.8^o##, which looks right.
 

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