Thermal Conductivity - Estimate Temperature

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Homework Statement



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Given an insulating case outer surface at 25C, radiates heat to surroundings at 20C. Find temperature inner surface.

Homework Equations





The Attempt at a Solution



The heat is conducted through a thickness of 2.5mm, with a temperature difference of 5oC. Thus ##\frac{\partial T}{\partial z} = 2000##. Using ##k = 0.02##:

We have a value for the flux:

[tex]J = k\frac{\partial T}{\partial z} = 40[/tex]

Using Stefan's Law:

[tex]J = \sigma T^4[/tex]

We get ##T = 163K##, and boy that is one cold case!(-110oC)
 
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You seem to think the 5oC difference is between the iPod and the outside of the case.
Looks to me as if that temperature difference is to be calculated from the flux.
Stefan's law works two ways: 25 to 20 should be something like [tex]J = \sigma \left ( T_{\rm case}^4 - T_{\rm environment}^4 \right )[/tex]
 
BvU said:
You seem to think the 5oC difference is between the iPod and the outside of the case.
Looks to me as if that temperature difference is to be calculated from the flux.
Stefan's law works two ways: 25 to 20 should be something like [tex]J = \sigma \left ( T_{\rm case}^4 - T_{\rm environment}^4 \right )[/tex]

That's right, because ##J## is the net flux (caused by a temperature gradient). The answer turns out to be ##26.8^o##, which looks right.