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rabbit44
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Homework Statement
A cylindrical wire of thermal conductivity k, radius a and resistivity p uniformly
carries a current I. The temperature of its surface is fixed at T0 using water cooling.
Show that the temperature T(r) inside the wire at radius r is given by
T(r) = T0 + p(I^2)(a^2 - r^2)/4pi^2a^4k
Homework Equations
del squared(T) = (c/k)dT/dt - H/k
Where H is heat generated per unit volume
The Attempt at a Solution
I took the system to be in a steady state as the temperature is fixed. So:
d2T/dr2 = -H/k
I took H = I^2 (pl/A)(1/lA)
= I^2p/pi^2a^4
Subbing this into my differential equation and integrating twice wrt r, I get:
T = -(I^2.p.r^2)/(2pi^2.a^4.k) + ba + c
Where b and c are integration constants. I think b must be zero but am not sure why. Then putting in T=T0 at r=a I would get a close answer but with a 2 on the bottom of the second term instead of a 4.
Where did I go wrong?!?
Thanks
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