Thermodynamic heat power problem

In summary, the problem is to determine the power needed for a carpet steamer to convert 2 kg of snow or ice to steam within 5 minutes, given that the snow/ice cannot be colder than -10°C. The necessary equations are Q=mCΔT, Q=mHv, and Q=mHf, and the known values are 2108 J/kg K for specific heat, 3.24*10^5 J/kg for latent heat of fusion, 4184 J/kg K for specific heat of water, and 2.26*10^6 J/kg for latent heat of vaporization. The attempted solution was to divide all the given values by two and then add them together, resulting in
  • #1
pasiman94
1
0

Homework Statement



Carpet steamer marketed for Greenland. Add up to 2 kg of snow or ice (no colder than -10°C) that will be converted to steam within 5 minutes. How powerful would the steamer need to be to make this claim? Know that 2108 J/kg K; Hf= 3.24*10^5 J/kg; Cwater= 4184 J/kg K; Hv = 2.26*10^6 J/kg.

Homework Equations



Q=mCΔT
Q=mHv
Q=mHf

The Attempt at a Solution


attempted to solve the equation by dividing all the givens by two and then adding them all up, however I know that it is not correct and the answer is P = 20156 W

Thanks
 
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  • #2
pasiman94 said:

Homework Statement



Carpet steamer marketed for Greenland. Add up to 2 kg of snow or ice (no colder than -10°C) that will be converted to steam within 5 minutes. How powerful would the steamer need to be to make this claim? Know that 2108 J/kg K; Hf= 3.24*10^5 J/kg; Cwater= 4184 J/kg K; Hv = 2.26*10^6 J/kg.

Homework Equations



Q=mCΔT
Q=mHv
Q=mHf

The Attempt at a Solution


attempted to solve the equation by dividing all the givens by two and then adding them all up, however I know that it is not correct and the answer is P = 20156 W

Thanks

What was the logic behind your approach? Why do you think it failed?
 

FAQ: Thermodynamic heat power problem

1. What is the definition of thermodynamic heat power?

Thermodynamic heat power is the amount of heat energy transferred from one object to another due to a temperature difference. It is usually measured in units of joules (J) or calories (cal).

2. How is thermodynamic heat power related to work?

Thermodynamic heat power is related to work through the first law of thermodynamics, which states that energy cannot be created or destroyed, but can be transferred from one form to another. This means that the heat energy transferred can be converted into work, or vice versa.

3. What is the difference between heat power and heat capacity?

Heat power is the rate at which heat energy is transferred, while heat capacity is the amount of heat energy required to raise the temperature of a substance by 1 degree Celsius. Heat capacity is an intrinsic property of a substance, while heat power is dependent on factors such as temperature difference and thermal conductivity.

4. How does temperature affect thermodynamic heat power?

The amount of heat power transferred between objects is directly proportional to the temperature difference between them. This means that a larger temperature difference will result in a greater amount of heat energy being transferred.

5. What are some real-life applications of thermodynamic heat power?

Thermodynamic heat power is used in many everyday applications, such as refrigerators, air conditioners, and car engines. It is also important in industries such as power generation, where steam turbines are used to convert heat energy into mechanical energy to generate electricity.

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