Calculating Work Done in Thermodynamic Problem Q

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In a thermodynamic problem involving a 2-m³ rigid tank containing nitrogen gas, the pressure increases from 500 kPa to 800 kPa due to heat transfer. Since the tank is rigid, there is no change in volume, meaning no work is done on or by the gas during this process. The increase in pressure is solely attributed to the heat added to the system, not mechanical work. Therefore, the work done in this scenario is zero. The focus remains on the heat transfer affecting the state of the nitrogen gas.
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Q. A 2-m3 rigid tank contains nitrogen gas at 500kPa and 300 K. Now heat is transferred to the nitrogen in the tank and the pressure of nitrogen rises to 800 kPa. The work done during this process is ...


Do we need to use

W = P2v2 - P1v1/ ( 1-n)

Some guidance requested please.

Thanks,
 
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Key words:
"rigid tank" meaning no change in volume. (I'm assuming this says a 2 cubic meter rigid tank.)
"heat transfered" meaning changes in state of the nitrogen are due to heat transfer, not work.

There is no work done, there is only heat transfer changing the state of the nitrogen.
 

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