Thermodynamic question involving work

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Homework Help Overview

The discussion revolves around a thermodynamic problem involving the calculation of work done during a reversible process, specifically transitioning from state P1V1 to P2V2. The original poster attempts to derive the work expression using the relation PVx = C, where x and C are constants.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the integration of the pressure-volume relationship to compute work, with some suggesting expressing pressure in terms of volume. The original poster questions how to incorporate changes in pressure and volume into their integral.

Discussion Status

Several participants have offered guidance on setting up the integral for work calculation. There is an ongoing exploration of the assumptions related to the constant k in the equation PVx = constant, with some questioning the justification for equating k at different states.

Contextual Notes

The original poster mentions a lack of access to their textbook and notes, which may limit their ability to provide a complete analysis. There is also a reference to potential algebraic errors in previous attempts.

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Homework Statement


Show that the work done by a reversible function from P1V1 to P2V2 is

W = (P1V1 -P2V2)/ (x - 1)

using the relation PVx = C where X and C are constants


Homework Equations



dW = PdV

The Attempt at a Solution



I'm going to have to update this more when i get home because i forgot my textbook and notebook

Basically what I did was draw a graph from P1V1 to P2V2 and the whole point is to find the area underneath the curve


My problem is I'm not sure how to include the change in pressure and the change in volume in this integral.

I'm basically getting (x-y)/xy where x and y are different volumes

Like i said i will update my work when i get home, but any help for now will be appreciated
 
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dw =PdV,there you are.
So to compute work,all you need to do is compute the definite integral of PdV from V1 to V2.
Express P in terms of V,by using the equation PVx=constant(say k),ie P=kV-x

Now Integrate KV-x from V1 toV2,and you are done,provided you put the limits nicely(substitute k=P1V1x in the 2nd term and k=P2V2x in the first term)
 
pabloenigma said:
dw =PdV,there you are.
So to compute work,all you need to do is compute the definite integral of PdV from V1 to V2.
Express P in terms of V,by using the equation PVx=constant(say k),ie P=kV-x

Now Integrate KV-x from V1 toV2,and you are done,provided you put the limits nicely(substitute k=P1V1x in the 2nd term and k=P2V2x in the first term)

funny thing is that if you are right i did that, and i guess i must have messed up my algebra. Curse the few first days of school
 
pabloenigma said:
dw =PdV,there you are.
So to compute work,all you need to do is compute the definite integral of PdV from V1 to V2.
Express P in terms of V,by using the equation PVx=constant(say k),ie P=kV-x

Now Integrate KV-x from V1 toV2,and you are done,provided you put the limits nicely(substitute k=P1V1x in the 2nd term and k=P2V2x in the first term)

I did do that, but do you justify that k=P2V2x=P1V1x?
 
In your question, PVx=constant is the equation of the process,ie this equation characterizes and defines the process the system is made to go through.This defines the way P and V of the system changes. So, P and V of the system always saties this equation. If P1V1, P2V2,P3V3 , etc are pressure and volume of the system in different points of time, then for all thes states, PiVi=k is satisfied.

So from the initial and final states we get

P1V1= P2V[/SUB]2[/SUB]=k.
Got it?
 

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