- #1

PhDeezNutz

- 708

- 449

- Homework Statement
- See Below

- Relevant Equations
- See Below

Let me start out by saying it's been a LONG time since I've touched any thermodynamics but I'm starting to think that the answer for all 3 parts are the exact same (at least for work)

Namely

##W = \int_{\frac{L^3}{2}}^{L^3} P(V) \, dV = NkT_0 \int_{\frac{L^3}{2}}^{L^3} \frac{1}{V} \, dV = NkT_0 \ln (2)##

My

**probably wrong**reasoning is as follows

for part (a) The only exchanged quantity is volume. There is no source of temperature difference that can cause the temperature of the gas to change so ##T## is constant. ##PV = NkT_0 \Rightarrow P =\frac{NkT_0}{V}## and we just integrate from initial to final volume.

for part (b) I contend that the temperature is also constant. If the right wall is held constant at ##T_0## and the gas is initially at ##T_0## then I don't see why the temperature of the gas would change.

for part (c) If the right side is at equilibrium with the surroundings on the right then I also don't see why temperature would change.

I'd imagine that I'm way off base so I'd just like to thank posters for their patience in advance.