Thermodynamics- Charging an air tank

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SUMMARY

The discussion focuses on determining the final temperature and mass of air in a scuba diver's 2ft³ air tank when filled to 120 psia from an initial state of 20 psia and 70°F. The relevant equations include the energy balance equation m_ih_i = m_2u_2 - m_1u_1, with initial enthalpy (h_1) at 133.86 Btu/lbm and internal energy (u_1) at 90.33 Btu/lbm. Participants suggest using the Ideal Gas Law and specific volume tables to find the final temperature (T) and mass (m_i) of the air injected into the tank.

PREREQUISITES
  • Understanding of thermodynamic principles, specifically energy balances.
  • Familiarity with the Ideal Gas Law and its applications.
  • Knowledge of property tables for air, including enthalpy and internal energy values.
  • Ability to perform mass balance calculations in thermodynamic systems.
NEXT STEPS
  • Learn how to apply the Ideal Gas Law in varying pressure and temperature conditions.
  • Study the use of property tables for air to find specific volumes and internal energy values.
  • Explore advanced thermodynamic concepts such as energy balance and mass flow rates.
  • Investigate the implications of using specific volume as a function of temperature and pressure in calculations.
USEFUL FOR

This discussion is beneficial for students and professionals in thermodynamics, particularly those working with gas systems, such as engineers and physicists involved in HVAC, scuba diving equipment design, or any applications involving compressed gases.

MacLaddy
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Homework Statement



A scuba diver's 2ft3 air tank is to be filled with air from a compressed air line at 120 psia and 100F. Initially, the air in this tank is at 20 psia and 70F. Presuming that the tank is well insulated, determine the temperature and mass in the tank when it is filled to 120 psia.


Homework Equations



m_ih_i = m_2u_2 - m_1u_1

From my property tables booklet.

h_1 = 133.86 Btu/lbm
u_1 = 90.33 Btu/lbm


The Attempt at a Solution



Not entirely sure where to take this. If I do just a mass balance I'll get m_i = m_2-m_1, but I'm not sure how this will help me.

If I could do an energy balance like this h_i=u_2-u_1, then it would be fairly simple to solve for the internal energy at the second state, and find the temperature. However, I don't think that's a legal move.

I've played with specific volumes, tried to find flow rates, and played with the Ideal Gas Law.

Any help is appreciated,

Thanks,
Mac
 
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Thank you Mod's for moving this to the appropriate forum. I wasn't sure exactly what category Thermodynamics fell into.
 
MacLaddy said:

Homework Statement



A scuba diver's 2ft3 air tank is to be filled with air from a compressed air line at 120 psia and 100F. Initially, the air in this tank is at 20 psia and 70F. Presuming that the tank is well insulated, determine the temperature and mass in the tank when it is filled to 120 psia.


Homework Equations



m_ih_i = m_2u_2 - m_1u_1

From my property tables booklet.

h_1 = 133.86 Btu/lbm
u_1 = 90.33 Btu/lbm


The Attempt at a Solution



Not entirely sure where to take this. If I do just a mass balance I'll get m_i = m_2-m_1, but I'm not sure how this will help me.

If I could do an energy balance like this h_i=u_2-u_1, then it would be fairly simple to solve for the internal energy at the second state, and find the temperature. However, I don't think that's a legal move.

I've played with specific volumes, tried to find flow rates, and played with the Ideal Gas Law.

Any help is appreciated,

Thanks,
Mac
How much mass m1 is in the tank to start with? Let mi represent the mass of air injected into the tank. How many moles are in the tank at the beginning and, in terms of mi, how many moles are in the tank at the end? Call T the final temperature. Use the ideal gas law to calculate the value of T in terms of mi. Now you only have 1 unknown. u2 is a function of T, which in turn is a function of mi. So use your equation m_ih_i = m_2u_2 - m_1u_1 and your table to solve for mi.

Incidentally, considering the magnitude of the pressure, maybe you're not comfortable using the ideal gas law. If your table has specific volume as a function of temperature and pressure, you can use that instead.

Chet
 
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