Thermodynamics Help: Ga(l) to Ga(g) at 1427 K

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SUMMARY

The discussion focuses on calculating the thermodynamic properties of liquid gallium (Ga(l)) transitioning to gaseous gallium (Ga(g)) at 1427 K. Participants derived equations for Gibbs free energy changes, specifically using the formula ΔG = RT ln(p2/p1). The equilibrium vapor pressure of liquid gallium at 1427 K is 0.1 torr, while the standard pressure is 1 bar. The conclusion confirms that liquid gallium will not spontaneously vaporize at this temperature under standard conditions.

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Homework Statement

The equilibrium vapor pressures of liquid gallium areT(K) 1302 1427 1623
p(torr) 0.01 0.1 1.0 a-Calculate the enthalpy, entropy and Gibbs energy changes for the process
b-Calculate the standard enthalpy, entropy, and Gibbs energy changes for the vapozation of liquid gallium at 1427 K. Under standard conditions the pressure of the gallium is 1 bar. Will liquid gallium 1427 K spontaneously form vapor with a pressu of 1 bar?

[tex] Ga(l) \rightarrow Ga(g, 0.1 torr)[/tex]

at 1427 K.

Heres what I derived so far

[tex] dG=Vdp<br /> dG=\frac{RT}{p}dp<br /> \Delta G=RTln\frac{p_2}{p_1}[/tex]

I'm not sure how to get [tex]p_1[/tex] to solve for [tex]\Delta G[/tex]
 
Last edited:
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I have solved this problem. It was quite simple actually.
If anyone wants me to post the solution, just let me know.
 

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