Thermodynamics Homework Help: Work, Internal Energy & Gas Compression

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SUMMARY

The discussion focuses on a thermodynamics problem involving the compression of a gas at a constant pressure of 0.800 atm, where the volume changes from 12.00 L to 3.00 L, resulting in 420 J of energy lost as heat. The work done on the gas can be calculated using the formula W = -PΔV, where P is the pressure in Pascals and ΔV is the change in volume. The change in internal energy (ΔU) can be determined using the first law of thermodynamics: ΔU = Q + W, where Q is the heat exchanged.

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  • Understanding of the ideal gas law
  • Familiarity with the first law of thermodynamics
  • Knowledge of pressure conversion from atm to Pascals
  • Basic skills in calculating work done in thermodynamic processes
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  • Calculate work done on the gas using W = -PΔV
  • Convert pressure from atm to Pascals for accurate calculations
  • Apply the first law of thermodynamics to find the change in internal energy
  • Explore real-world applications of gas compression in thermodynamic systems
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Homework Statement


A gas is compressed at a constant pressure of 0.800 atn from 12.00 L to 3.00 L. In the process, 420 J of energy leaves the gaas by heat.

a) What is the work done on the gas?

b) what is the change in its internal energy?


Homework Equations


1atm = 1.0135e5 N/m^2
1Pa = 1 N/m^2


The Attempt at a Solution

 
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The Attempt at a Solution

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