Thermodynamics Pressure Problem Help

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SUMMARY

The pressure at the bottom of a 1000 m thick ice cap with a density of 920 kg/m³ is calculated using the equation ΔP = ρgH, resulting in a pressure increase of 9022 kPa. Adding the initial atmospheric pressure of 101.325 kPa, the total pressure at the bottom is 9123 kPa. To determine the corresponding melting temperature, a pressure-temperature (P-T) chart is utilized, yielding an approximate temperature of 275 K. This analysis is crucial for understanding the thermodynamic properties of ice under pressure.

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  • Understanding of basic thermodynamics concepts
  • Familiarity with pressure calculations using ΔP = ρgH
  • Knowledge of steam tables and P-T charts
  • Basic principles of ice melting and phase transitions
NEXT STEPS
  • Study the use of steam tables for various substances
  • Learn about phase transitions and the significance of P-T charts
  • Explore the effects of pressure on melting points in different materials
  • Investigate the thermodynamic properties of ice and water at varying pressures
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Students studying thermodynamics, physics enthusiasts, and professionals involved in climate science or materials science who need to understand the effects of pressure on ice and melting temperatures.

MechE2015
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Homework Statement



The ice cap on the North Pole could be 1000 m thick with a density of 920 kg/m3. Find the pressure at the bottom and the corresponding melting temperature.

Homework Equations



Steam tables
ΔP = ρgH

The Attempt at a Solution



ΔP = (920 kg/m3)*(9.28 m/s2)*(1000) = 9022 kPa
P = Pinitial + 9022 kPa

I have no idea how to find initial pressure, which I think is my main information missing, then from there I would need to find the corresponding temperature.
 
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MechE2015 said:

Homework Statement



The ice cap on the North Pole could be 1000 m thick with a density of 920 kg/m3. Find the pressure at the bottom and the corresponding melting temperature.

Homework Equations



Steam tables
ΔP = ρgH

The Attempt at a Solution



ΔP = (920 kg/m3)*(9.28 m/s2)*(1000) = 9022 kPa
P = Pinitial + 9022 kPa

I have no idea how to find initial pressure, which I think is my main information missing, then from there I would need to find the corresponding temperature.
Welcome to Physics Forums.

The initial pressure is the pressure at the top of the ice cap ... which is the pressure pretty much anywhere on the surface of Earth. :wink:

EDIT added:
You're a tad slow today, SteamKing! :smile:
 
What's on top of the polar ice cap? That's how you find the initial pressure.

Hint: it blows past you in the breeze.
 
Alright, so the pressure at the surface is 1 atm = 101.325 kPa, which gives me:

P = Po + ΔP = 101.325 + 9022 = 9123 kPa

From here, finding temperature would be found by maybe a P-T chart, where the substance goes from solid -> liquid? Around 275 K is what I get.
 
MechE2015 said:
Alright, so the pressure at the surface is 1 atm = 101.325 kPa, which gives me:

P = Po + ΔP = 101.325 + 9022 = 9123 kPa
Looks good.
From here, finding temperature would be found by maybe a P-T chart, where the substance goes from solid -> liquid?
Yes, that should work.
Around 275 K is what I get.
That's not a terrible approximation, though it is possible they are looking for a more accurate value. I'm not saying they are, just saying it's a possibility.

For a more accurate value, think about how does the 9000 kPa temperature on the chart compare to the temperature at 101 kPa?

p.s to SteamKing: I think this is getting more into your territory than mine. :smile:
 

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