Thermodynamics pressure-temperature-volume problems

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Homework Help Overview

The discussion revolves around thermodynamics problems involving pressure, temperature, and volume changes in gases, as well as heat transfer in calorimetry involving different materials. The original poster presents two distinct problems: one related to gas laws and another concerning thermal equilibrium in a calorimeter with lead, water, and aluminum.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationships between pressure, volume, and temperature using the ideal gas law for the first problem. In the second problem, they discuss the conservation of energy in thermal equilibrium and the calculation of specific heat for lead.

Discussion Status

Some participants provide insights into the equations governing the problems and suggest corrections to the original poster's approach. There is acknowledgment of the age of the homework question, with reminders about the forum's guidelines on providing assistance.

Contextual Notes

Participants note that the original poster's question is quite old, which raises considerations about the appropriateness of providing direct answers versus guidance. There is also mention of the need to adhere to forum rules regarding homework help.

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Homework Statement


When the volume of a gas is reduced with fp% and the gas is heaten with ΔT K, the pressure of it grows with fp%.Find initial temperature Ti.
Application: fv%= 20%; ΔT 12 K; fp% = 30%


2.A aluminium calorimeter with the mass m1 contains the mass m2 of water heated at T1.In the water from calorimeter is inserted a body of lead(Pb) at mass m3 at the temperature of T3 (>T1).The termic equilibrum is set at the temperature T.We have the specific heats c1 and c2 of the aluminium and of the water.Find the specific heat c3 of the lead.
Application: m1 = 41,6 g; m2 = 0,232 kg; T1= 288 K; m3 = 0,1 kg; T3 = 373 K; T =289K; c1 = 920 J/(kg * K); c2 = 4180 J/(kg * K).

Homework Equations



At 1 the T1 = 300k and at 2 c3 = 120 J(kg *K)

The Attempt at a Solution

 
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In the equilibrium of temperature between the calorimeter and lead, you have that the heat given by the lead when reducing its temperature, is the same heat that the water and the aluminum calorimeter receive to increase its initial temperature until the equilibrium temperature.
in formulas

Q = m_{3}Ce_{Pb} (T_{3}-T) = m_{1}Ce_{H2O} (T_{1}-T) + m_{2}Ce_{Al} (T_{1}-T)
from the last equality, clear and calculate Ce_ {Pb}
 
The first problem is solved very easily with ##P_1 V_1=n_1 RT_1 ## , and writing ##PV=nRT ## again with the conditions that are applied.
 
Richard R Richard said:
In the equilibrium of temperature between the calorimeter and lead, you have that the heat given by the lead when reducing its temperature, is the same heat that the water and the aluminum calorimeter receive to increase its initial temperature until the equilibrium temperature.
in formulas

Q = m_{3}Ce_{Pb} (T_{3}-T) = m_{1}Ce_{H2O} (T_{1}-T) + m_{2}Ce_{Al} (T_{1}-T)
from the last equality, clear and calculate Ce_ {Pb}
I think on the right side you need ##T-T_1 ##. Otherwise, very good.
Meanwhile, this is a very old homework. (9 years old). I don't think the OP is needing a response anymore.
 
Last edited:
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Hello, I am new to the forum, the problem is easy and I answered.
you are right about reversing signs on the right side.
I had started from
\displaystyle{\sum Q_i=\sum m_iCe_i(T_i-T)=0}
conservation law...
but copy and paste, forget to reverse the signs , sorry, thank you.
 
Richard R Richard said:
Hello, I am new to the forum, the problem is easy and I answered.
Keep in mind that it was okay for you to answer this homework question because it is 9 years old. In general, we do not provide answers to homework questions, especially those where the OP showed little effort.

We give hints, ask questions, find mistakes, etc. But we don't do a student's homework for them here. Welcome to PhysicsForums! :smile:
 
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