[Thermodynamics] Quick question about ''Cut-off ratio'' in the Diesel Cycle.

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SUMMARY

The discussion centers on the "cut-off ratio" in the Diesel Cycle, specifically its definition and relationship to the expansion ratio. Two different definitions were presented: one as r_E = V_1/V_3 and the other as r_E = V_3/V_2. The participant clarified that the expansion ratio is essentially the same as the compression ratio, except in engines with offset cylinder banks or crankshafts, such as the Toyo Aygo 1.0 and Honda Insight 1.0, where these ratios differ due to unique design considerations.

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[SOLVED] Quick question about ''Cut-off ratio'' in the Diesel Cycle.

So I've been studying the Diesel Cycle, and I've come up with something called the ''cut-off ratio'', which is simply a name for the ratio of expansion r_E.

But I'm getting different definitions for this ratio.

For example, in the below link the expansion ratio is given by r_E = \frac{V_1}{V_3}

http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/diesel.html#c2

And in this other link the expansion ratio is given differently by r_E = \frac{V_3}{V_2}

http://www.taftan.com/thermodynamics/DIESEL.HTM

I'm confused, can someone enlighten me please, are those expressions similar, if yes, how so?

Thanks.
 
Last edited:
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I've already found out what I was getting wrong.

Thanks for all the help I was provided.
 
The expansion ratio is basically the compression ratio, unless we're talking 'bout an engine with offset cylinder bank/crankshaft, which I've heard of very few, all of which being of small displacement because of balancing issues. The Toyo Aygo 1.0 petrol is one example. The Honda Inshight 1.0 is another.

With such engines, the compression and expansion ratios differ and the intake and compression, expansion and exhaust do not last for as many crank degrees.
 

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