(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A cubical styrofoam cooler 80cm on a side and 2.0 cm thick contains 2.0kg of ice at 0C. If it takes four hours for the ice to melt what is the outside temperature? K(st)=.02 w/m*K

2. Relevant equations

H=-KA (ΔT/ΔX)

(conductive heat flow)

3. The attempt at a solution

Area: 6(a)^2= 6(.8)^2= 3.8m^2

Δx=.02m

K(st)=.02 w/m*K

H=-.02 w/m*K(3.8m^2) (ΔT/.02m)

So I used the formula for the conductive heat flow, but I still have two unknowns. I know H is ΔQ/Δt, but I am asked for the time. I had two questions in regards to this problem:

1. for the area do I find the total surface area or just one side?

2. what temperature change ΔT should I set the ΔQ formula if I am assuming the ice is melting?

Thanks for the help!

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Thermodynamics with styrofoam cooler

**Physics Forums | Science Articles, Homework Help, Discussion**