(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A cubical styrofoam cooler 80cm on a side and 2.0 cm thick contains 2.0kg of ice at 0C. If it takes four hours for the ice to melt what is the outside temperature? K(st)=.02 w/m*K

2. Relevant equations

H=-KA (ΔT/ΔX)

(conductive heat flow)

3. The attempt at a solution

Area: 6(a)^2= 6(.8)^2= 3.8m^2

Δx=.02m

K(st)=.02 w/m*K

H=-.02 w/m*K(3.8m^2) (ΔT/.02m)

So I used the formula for the conductive heat flow, but I still have two unknowns. I know H is ΔQ/Δt, but I am asked for the time. I had two questions in regards to this problem:

1. for the area do I find the total surface area or just one side?

2. what temperature change ΔT should I set the ΔQ formula if I am assuming the ice is melting?

Thanks for the help!

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# Homework Help: Thermodynamics with styrofoam cooler

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