1. The problem statement, all variables and given/known data Three moles of an ideal gas are taken around the cycle abc. For this gas, Cp= 29.1 J/mol K. Process ac is at constant pressure, process ba is at constant volume, and process cb is adiabatic. The temperatures of the gas in states a, c, and b are Ta= 300K, Tb= 490K, Tc= 600K. Calculate the total work W for the cycle. 2. Relevant equations W=P(delta)V=nR(delta)T W=-(delta)E=-nCv(delta)T 3. The attempt at a solution Total work is the sum of the work done at each process Total Work = Wac + Wcb + Wba W at ac = isobaric process = nR(delta)T W at cb = adiabatic process = -nCv(delta)T W at ba = isochoric process, therefore W= 0 Cp = 29.1 = 3.5R so Cv = 2.5R = 20.8 Total Work = (3)(8.31)(190) - (3)(20.8)(110) + 0 = 4,736.7 - 6,864 = -2,127.3 I have to submit this for my homework, but I'm not sure if this is correct. Could you please check this for me?