Thermodynamis of air in a basketball

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Homework Statement


A player bounces a basketball on the floor, compressing it to 80.0 % of its original volume. The air (assume it is essentially N_2 gas) inside the ball is originally at a temperature of 20.0 C and a pressure of 2.00 atm. The ball's diameter is 23.9 cm

Temperature at maximum compression equals 47.4 C

By how much does the internal energy of the air change between the ball's original state and its maximum compression?
[tex]\Delta[/tex]U=?

Homework Equations



[tex]\Delta[/tex]U=nC_v[tex]\Delta[/tex]T
C_v=20.76

The Attempt at a Solution



n=.0000058657

[tex]\Delta[/tex]U=.00333657
but that's not right
 
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Start with the first law

Q-W=ΔU

now no heat is being added to the system so Q=0

You're left with ΔU= -W. What is the work done on the ball?