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Thermodynamis of air in a basketball

  1. Sep 27, 2009 #1
    1. The problem statement, all variables and given/known data
    A player bounces a basketball on the floor, compressing it to 80.0 % of its original volume. The air (assume it is essentially N_2 gas) inside the ball is originally at a temperature of 20.0 C and a pressure of 2.00 atm. The ball's diameter is 23.9 cm

    Temperature at maximum compression equals 47.4 C

    By how much does the internal energy of the air change between the ball's original state and its maximum compression?
    [tex]\Delta[/tex]U=?

    2. Relevant equations

    [tex]\Delta[/tex]U=nC_v[tex]\Delta[/tex]T
    C_v=20.76
    3. The attempt at a solution

    n=.0000058657

    [tex]\Delta[/tex]U=.00333657
    but thats not right
     
  2. jcsd
  3. Sep 27, 2009 #2

    rock.freak667

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    Homework Helper

    Re: Thermodynamics

    Start with the first law

    Q-W=ΔU

    now no heat is being added to the system so Q=0

    You're left with ΔU= -W. What is the work done on the ball?
     
  4. Sep 27, 2009 #3
    Re: Thermodynamics

    W=nC_v(T_1-T_2)
    that is the same thing i was using
     
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